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expeople1 [14]
4 years ago
14

Solve the quadratic equation by completing the square. x^2+12x+52=0

Mathematics
1 answer:
White raven [17]4 years ago
6 0

Answer:

(x + 6)² + 16 = 0

Step-by-step explanation:

To complete the square we will first need to get our equation to look like: x² + bx = c

Here we have x² + bx + c = 0 → x² + 12x + 52 = 0

  • First we need to subtract our c, in this case 52, from both sides to get x² + 12x = -52
  • We then need to add (\frac{b}{2} )^{2} to both sides of the equation
  • Here our b value is 12, so plugging this into our formula we get (\frac{12}{2} )^{2} =(6)^{2} =36
  • Adding 36 to both sides our equation becomes: x² + 12x + 36 = -52 + 36
  • Then combining like terms on the right side we get x² + 12x + 36 = -16
  • Now making our left side of the equation into a perfect square we get: (x + 6)² = -16
  • Finally adding the 16 to both sides of the equation we get: (x + 6)² + 16 = 0

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Find the distance between -3 and 4. A) -12 eliminate b) -7 c) -1 d) 7
n200080 [17]

The formula of a distance between A and B = |B - A|.

We have -3 and 4. Substitute:

|4 - (-3)| = |4 + 3| = |7| = 7

<h3>Answer: d) 7</h3>
8 0
3 years ago
From families with four children a family is chosen at random. Let X be the number of boys in the family. Calculate and sketch t
alisha [4.7K]

Solution :

Given :

X = the number of boys in a family of four children

Families having four children are chosen randomly.

The gender distribution in the four child family are equally probable.

Thus,

 X                P(X)                                          CDF

0             ^4C_0 (1/2)^{4}        = 1/16                     \frac{1}{16}

1               ^4C_1 (1/2)^{4}       = 1/4                       \frac{5}{16}

2                ^4C_2 (1/2)^{4}      = 3/8                      \frac{11}{16}

3                ^4C_3 (1/2)^{4}      = 1/4                       \frac{15}{16}

4                  ^4C_4 (1/2)^{4}    = 1/16                      1

4 0
3 years ago
Solve the inequality for x<br> 3^(6x+18)&lt;27^(3x)
Lera25 [3.4K]

Answer:

\displaystyle x > 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}
  • Solving exponential equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 3^{6x + 18} < 27^{3x}<em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Rewrite:                                                                                                             \displaystyle 3^{6x + 18} < 3^{3(3x)}
  2. Set:                                                                                                                     \displaystyle 6x + 18 < 3(3x)
  3. Factor:                                                                                                               \displaystyle 3(2x + 6) < 3(3x)
  4. [Division Property of Equality] Divide 3 on both sides:                                  \displaystyle 2x + 6 < 3x
  5. [Subtraction Property of Equality] Subtract 3x on both sides:                       \displaystyle -x + 6 < 0
  6. [Subtraction Property of Equality] Subtract 6 on both sides:                        \displaystyle -x < -6
  7. [Division Property of Equality] Divide -1 on both sides:                                 \displaystyle x > 6
8 0
3 years ago
Read 2 more answers
6x - 3y = -6<br> y = 2x + 2
Verizon [17]

Answer:

y=0, x=1

Step-by-step explanation:

6x-3y= -6 ...... equation 1

y =2x+2 ..... equation 2

subtract 2x from both sides

y-2x=2x-2x+2

y-2x=2

6x-3y= -6

y-2x=2

Rearrange

6x-3y= -6 ........x1

-2x +y=2............x3

6x-3y= -6

-6x +3y=2

0y=0

y=0

substitute y=0 in equation 1

6x-3xo= -6

6x= -6

x-6/6

x = -1

4 0
4 years ago
How do i do this.
Sonbull [250]
You have to multiply both numbers with the same factor. What I mean, 475/58 gives you 8 R 11. Now let's try this, (475x2=950) and (58x2= 116) so our new numbers are 950/116 which gives us the same answer 8 R 11 ! I hope this helped.. But let's try another one, keep in mind, you can multiply the number by any factor AS LONG AS you multiply them with the SAME factor. So if you multiply 475 by 5, then you have to multiply the 58 by 5 as well. Now let's try, (475x5=2375) and (58x5= 290) therefore, 2375/290 = which gives you 8 R 11 ! I hope I helped . I am a Palestinian student in Palestine in grade 11 and you just brought me back to grade 4 memories ! math is fun when you get it (: good luck
6 0
3 years ago
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