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3 years ago

So you wanna go shopping and you have 45$ to spend. you see a t shirt you like

Mathematics

1 answer:

Travka [436]3 years ago

8 0

Answer:

The holiday sweater and the pants will save the most money with having $22 left.

Step-by-step explanation:

have a good day :)

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Get money to answer this.

IRINA_888 [86]

Answer:

Step-by-step explanation:

i think it is but it might be wrong

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3 years ago

4. The pitcher's circle on a baseball field has a diameter of 6 feet. How

vivado [14]

Answer:

3.14*6

Step-by-step explanation:

answer=18.84

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3 years ago

Read 2 more answers

The midpoint of AB is M(-1, –4). If the coordinates of A are (-3, -7), what are

quester [9]

Answer:

Step-by-step explanation:

If M(-1, 4) is midpoint of AB then:

$x_M-x_A=x_B - x_M\qquad\quad\ \wedge\qquad y_M-y_A=y_B - y_M\\\\ -1-(-3)=x_B-(-1)\qquad\wedge\qquad -4-(-7)=y_B -(-4)\\\\ -1+3=x_B+1\qquad\qquad\wedge\qquad\ \ -4+7=y_B+4 \\\\ {}\qquad x_B=1\qquad\qquad\wedge\qquad\qquad \ y_B=-1$

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3 years ago

Which is an equation of the line that passes through the point (8,7) and is perpendicular to the line whose equation is y = 4x-1

algol [13]

Answer:

Y = -1/4x + 5

Step-by-step explanation:

7 0

3 years ago

The demand function for q units of a product at $p per unit is given by p(q + 3)2 = 100,000. Find the rate of change of quantity

wariber [46]

Answer:

-0.625 unit

Step-by-step explanation:

Given that:

$p(q+3)^2 = 100, 000$

where;

p = price

q = quantity

To find the rate of change of quantity (q) with respect to price (p) we go by the differentiation

$(q+3)^2\frac{dp}{dp} +p^2(q+3)\frac{dq}{dp}=0$

$(q+3)^2 +p^2(q+3)\frac{dq}{dp}=0$

$\frac{dq}{dp}=\frac{-(q+3)}{2p}$

when P =40

Then 4(q+3)² = 100, 000

(q+3)² = $\frac{100,000}{4}$

(q+3)² = 25,000

(q+3) = $\sqrt{2500}$

q+ 3 = 50

q = 50 -3

q = 47

NOW; $\frac{dq}{dp}=\frac{-(q+3)}{2p}$

$\frac{dq}{dp}=\frac{-(47+3)}{2*40}$

$\frac{dq}{dp}=\frac{-47-3}{2*40}$

$\frac{dq}{dp}=\frac{-50}{80}$

$\frac{dq}{dp}=-0.625$

Thus, the rate of change of quantity with respect to price when p = $40 is -0.625 unit.

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4 years ago