A) x – 7 = -7(6y + 5)
x – 7 = -42y + -35
x – 7 + 35 = -42y
x + 28 = -42y
y = (1/42)x – 14/21
c) y – 7 = 7(x + 5)
y – 7 = 7x + 35
y = 7x + 42
b) y – 7 = -7(x + 5)
y – 7 = -7x -35
y = -7x – 28
d) y + 7 = 7(x + 5)
y + 7 = 7x + 35
y = 7x + 28
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have the following equation:

We manipulate algebraically to write the equation of the slope-intersection form:

We check if the given point belongs to the equation:

The point does not belong to the equation.
ANswer:

Answer:
-x - 4
Step-by-step explanation:
8=m-7
add 7 to both sides
m=15
Answer:
no because thats an obtuse angle and there has to be an acute triangle to from a triangle so no
Step-by-step explanation: