Take the original coordinate (x,y)
to reflect over x-axis change it to (x,-y)
*basically change the sign of y*
to translate 6 units left (x-6,y)
* basically subtract 6 from x
So your new point should be (x-6,-y)
6) 18,26,34
Add 8 each time
… 42,50,58,66,74,82,90,98,106,114,122,130
The 15th term in the sequence would be 130
Answer:
B. {2,6,8}
Step-by-step explanation:
Since the range is your output, also known as your Y's, whenever you list them, they MUST be listed in order.
What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)
Three consecutive integers are . . . x, x+1, and x+2
The smallest two are . . . x and x+1
Their product is . . . . . x(x+1)
5 times the largest one is . . . 5(x+2)
5 less than that is . . . . . . 5(x+2)-5
Now, the conditions of the problem say that <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .
Eliminate parentheses: x² + x = 5x + 10 - 5
Combine like terms: x² + x = 5x + 5
Subtract 5x from each side: x² - 4x = 5
Subtract 5 from each side: <u>x² - 4x - 5 = 0</u>
You could solve that by factoring it, or use the quadratic equation.
Factored, it says that (x + 1) (x - 5) = 0
From which <em>x = -1</em>
and <em>x = +5</em>
We only want the positive results, so our three consecutive integers are
5, 6, and 7 .
To answer the question, the smallest one is <em><u>5 </u></em>.
<u>Check</u>:
5 x 6 ? = ? (7 x 5) - 5
30 ? = ? (35) - 5
30 = 30
yay !
Answer:
8x+24
Step-by-step explanation:
Solve
3 times x = 3x
3 time 8 = 24
+5x
Combine like terms
3x+5x=
8x+24
Hope this helped
Please mark brainliest
So i can rank up ;D
