Answer:
a. v(t)= -6.78
+ 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=
=
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒ v' + kv = g ⇒ [v]' = g. Integrating, we have
∫ [v]' = ∫g
v = 
+ c
v(t)= + c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c
= 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78. m/s = - 6.78 + 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78
+ 16.33 m/s = 16.328 m/s ≅ 16.33 m/s
Answer:
4000 times greater
Answer:
3x + 2 = 59
Step-by-step explanation:
because the total is 59 so is definetly =59
and no of oranges in bag so there are 3 bags it means its 3x so the equation is 3x + 2 = 59
Hope it will help you
Lots of love from nepal <3 :)
Answer:
a. Maurice walked farther.
b. 0.62 m
Step-by-step explanation:
Maurice
4.1 × 1.8 = 7.38 miles
Junnie
2.5 × 3.2 = 8 miles
This shows that Junnie walked more than Maurice.
8 - 7.38 = 0.62
Junnie walked 0.62 m more than Maurice
