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HACTEHA [7]
3 years ago
10

Using the picture what is the equation of the line in point slope form?*

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

y=2/5(x+5)-3

Step-by-step explanation:

my work is attached

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PLEASE ANSWER THIS ASAP, I WILL BE GIVING YOU A THANKS! .
timama [110]

Answer:

D.) 12

Step-by-step explanation:

16x - 3(4x + 5) = 2x + 9

16x - 12x - 15 = 2x + 9

4x - 2x = 15 + 9

2x = 24

2x/2 = 24/2

x = 12

Check:

16x - 3(4x + 5) = 2x + 9

16(12) - 3(4(12) + 5) = 2(12) + 9

192 - 3(48 + 5) = 2(12) + 9

192 - 3(53) = 24 + 9

192 - 159 = 33

33 = 33

3 0
2 years ago
dale is driving to Miami. suppose that the distance (in miles) is a linear function of his total driving time (in minutes). dale
nexus9112 [7]
Considering there is a function (relationship) and that it is linear, the distance will change proportionally to time constantly. In other words, we are taking the speed to be constant throughout the journey.
If we let:
t = time (min's) driving
d = distance (miles) from destination
Then we can represent the above information as:
t = 40: d = 59
t = 52: d = 50
If we think of this as a graph, we can think of the x-axis representing time and the y-axis representing the distance to the destination. Being linear, the function will be a line, i.e. it will have a constant gradient. If you were plot the two points inferred from the information and connect the two dots, you will get a declining line (one with a negative gradient) representing the inversely proportional relationship or equally, the negative correlation between the time driving and the distance to the destination. The equation of this line will be the linear function that relates time and the distance to the destination. To find this linear function, we do as follows:

Find the gradient (m) of the line:
m = Δy/Δx
In this case, the x-values are t-values and our y-values are d-values, so:
Δy = Δd
= 50 - 59
= -9
Δx = Δt
= 52 - 40
= 12
m = -9/12 = -3/4
Note: m is equivalent to speed with units: d/t

Use formula to find function and rearrange to give it in the desired format:
y - y₁ = m(x - x₁)
d - 50 = -3/4(t - 52)
4d - 200 = -3t + 156
4d + 3t - 356 = 0

Let t = 70 to find d at the time:
4d + 3(70) - 356 = 0
4d + 210 - 356 = 0
4d - 146 = 0
4d = 146
d = 73/2 = 36.5 miles

So after 70 min's of driving, Dale will be 36.5 miles from his destination.
3 0
3 years ago
(I NEED THIS ASAP) Find the slope of the line. Use points shown, (-1,-5) and(2,1)
patriot [66]

Answer:

2/1 or 2

Step-by-step explanation:

You go up 6 and over 3 simplify 6/3 to 2/1=2

3 0
2 years ago
Find the measure of each angle indicated.<br> A) 95°<br> C) 26°<br> B) 92°<br> D) 20°
riadik2000 [5.3K]

Answer:

D) 20°

Step-by-step explanation:

Using the triangle sum theorem, you know that every triangle's interior angles add up to 180°. Therefore the bottom triangle's missing angle can be found by giving it the variable x.

57° + 30° + x = 180°

Simplify: 87° + x =180°

x=93°

By the vertical angles theorem, the vertical angle directly across this angle is congruent to this one. Meaning that the top triangle's angle are 67°, 93°, and unknown, which we can assign y. We can use the same method from above here.

67° + 93° + y = 180°

Simplify: 160° + y = 180°

y=20°

6 0
3 years ago
Read 2 more answers
The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc
AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

p \propto \dfrac{1}{d}

Introducing the constant of proportionality

p = \dfrac{k}{d}

If 150 pounds is required for a distance of 10 inches from the object

  • p=150 pounds
  • d=10 inches

150 = \dfrac{k}{10}\\\\k=1500

Therefore, the relationship between p and d is:

p = \dfrac{1500}{d}

When d=3 Inches

p = \dfrac{1500}{3}\\\implies p=500$ pounds

The pressure applied when the distance is 3 inches is 500 pounds.

4 0
3 years ago
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