first find the length of the larger base.
Which would be the bottom in this case.
Then, find the sum of all of the sides.
It's important to note that since this is an isosceles trapezoid, both of the non-parallel sides will have the same length.
<span>A regular octagon is a closed figure with sides of the same length and internal angles of the same size. so if it is rotated 360 degrees it should coincide with its preimage after every 45 degrees. So 360/45= 8 times</span>
The given points are
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or

The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:

The magnitude is √(10).
The answer is 3/4 ft² = 0.75 ft²
The area (A) of the parallelogram with altitude a and base b is:
A = a * b
We have:
A = ?
a = 6 in
Since 1 inch is 0.083 feett, then 6 inches is
a = 6 * 0.083 ft = 0.498 ft ≈ 0.5 ft = 1/2 ft
b = 1 1/2 ft = 1 + 1/2 ft = 2/2 + 1/2 ft = 3/2 ft
_______
A = a * b
a = 1/2 ft
b = 3/2 ft
A = 1/2 * 3/2 = 3/4 ft² = 0.75 ft²