Answer:
5
Step-by-step explanation:
20/4 is 5 (4 sides)
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
25% of people leave early as 6 is 1/4 of 24. You can solve this by dividing 6 by 24 (I believe, maybe check with someone on that but that’s how i figured it out).
Answer:
The range is y> 9
Step-by-step explanation:
