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Gemiola [76]
3 years ago
6

I hate math! Help please!

Mathematics
1 answer:
Igoryamba3 years ago
4 0
5. D
6. D
9. D
10. D
Not joking, they're all D...
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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ASHA 777 [7]

The area of the given figure is 576 cm sq.

The perimeter of the given figure is 96 cm.

Step-by-step explanation:

The shape consists of one semicircle and one square which is cut by a semicircle.

<u>To find Area:</u>

Find the area of semicircle= (πr^2)/2

where r is the radius= diameter/2= 24/2= 12 cm

Area of semicircle= π(12)(12)/2= 144π/2= 72π cm sq.

Find the area of square= a^2

where a is the side of square, a=24 cm.

Area of the square= 24*24= 576 cm sq.

To find the total area of the given figure,

Area of the figure= Area of semicircle+(area of square- area of semicircle)

                             = 72π+576-72π =576 cm sq.

<u>To find perimeter:</u>

Perimeter of semicircle= (2πr)/2

                                       = (2*12*π)/2= 12π cm

Perimeter of square= 4a =4*24 =96 cm

Perimeter of the given figure=  perimeter of semicircle+(perimeter of                        square- perimeter of semicircle)

                                                 = 12π+96+12π =96 cm.                            

4 0
3 years ago
Bethany has a circular table that she needs to carry inside her house to paint. Her front door is a rectangle and has a width of
RoseWind [281]
I thought I knew this but nvm
4 0
3 years ago
Read 2 more answers
During one week, David worked 16 hours at his normal hourly rate and
asambeis [7]

Answer:

43.49

Step-by-step explanation:

let his normal hourly rate be x

16x+7x/2=848

39x/2=848

x=848 ÷ 39/2

=43.48717

6 0
3 years ago
Read 2 more answers
The next number in the arithmetic sequence 10,23,36,? Is
rjkz [21]
It would be 49
10+13=23
23+13=36
36+13=49
I think this is right
6 0
4 years ago
Three machines A, B, and C produce 55%, 25% and 20% respectively. The percentages of defective output are 3.5%, 4.5% and 5.5%. I
pishuonlain [190]

We are given the following information concerning the three production machines;

\begin{gathered} Of\text{ the total production;} \\ A=55\text{ \%}=0.55 \\ B=25\text{ \%}=0.25 \\ C=20\text{ \%}=0.20 \end{gathered}

Also, we are given the percentage of defective output as follows;

\begin{gathered} A=3.5\text{ \%}=0.035 \\ B=4.5\text{ \%}=0.045 \\ C=5.5\text{ \%}=0.055 \end{gathered}

Therefore, if an item is selected randomly, the probability that the item is defective would be;

\begin{gathered} P\lbrack defective\rbrack=(0.55\times0.035)+(0.25\times0.045)+(0.20\times0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}

ANSWER:

The probability that the item is defective would be 0.0415

6 0
1 year ago
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