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USPshnik [31]
4 years ago
5

por reparar un campo de 7 hectáreas de superficie, un labrador cobra $21.315 ¿cuanto cobraría si la superficie del campo midiera

12 hectáreas ?
Mathematics
1 answer:
bazaltina [42]4 years ago
8 0

Answer:

que?

Step-by-step explanation:


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Which function defines the sequence -16,-22,-28,-34 where f(10)= -70
-Dominant- [34]

Answer:

f(n) = -6n - 10.

Step-by-step explanation:

This is arithmetic sequence with first term a1 = -16 and common difference d = -6.

So f(n) = a1 + d(n - 1)

= -16 - 6(n - 1)

= -16 - 6n + 6

= -6n - 10.

Checking:

f(10) = -6(10) - 10 = -70.

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3 years ago
What is every password comnason with four numbers through 1234567890
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There is 10,000 possible combinations for the numbers 0-9 
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Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag
VLD [36.1K]

Hey~freckledspots!\\----------------------

We~will~solve~for~i^{425}!

Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\

Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------

Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------

Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------

Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------

Answer:\\\large\boxed{-1+i}\\----------------------

Hope~This~Helped!~Good~Luck!

8 0
4 years ago
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USING PARALLEL LINES Find the values of x and y. Explain your reasoning.<br><br> I don’t understand
AfilCa [17]

Step-by-step explanation:

x=180°-109°=71° (Interior angles)

y= 71° (Alternate angles)

y= 180°- 65°=115° (Adjacent angles)

x= 65° (Corresponding angles)

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3 years ago
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What is the unit rate and state rate of 253 for 20 hours?
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The unit rate is 12.65 per hour. 
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