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DedPeter [7]
3 years ago
5

Find the equation of a circle whose endpoints of the diameter are (15, - 3) and (7,3). The equation of the circle is (Simplify y

our answer. Type your answer in standard form.)​
Mathematics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

(x - 11)² + y² = 25

Step-by-step explanation:

First find the center

O = ( (15 +7 / 2), (-3 + 3)/2 )

O = (11, 0)

Then find the radius squared

use the distance formula from the center to either end point of the diameter

r² = (15 - 11)² + (-3 - 0)²

r² = 16 + 9

r² = 25

Formula for circle

(x - h)² + (y - k)² = r²

(h, k) is the center = (11, 0)

The equation is

(x - 11)² + y² = 25

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I don't know how to answer this​
netineya [11]

Answer:

when the input is 3 the output is 1

Step-by-step explanation:

inputs would basically be the x coordinates while outputs are the y coordinates. when you put in the x coordinate of 3, the y coordinate of 1 is what shows up as the output. (3,1) are the coordinates on the line

7 0
2 years ago
Plz help, answer the question below
Afina-wow [57]

\sqrt[6]{x^{16}} =\sqrt[6]{x^{12} \cdot x^{4}}=x^2\sqrt[6]{x^{4}}

5 0
3 years ago
When ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″, vertex (note: please enter your response using apostrophes ins
maria [59]
(A) because it is reflecting over the x-axis.
7 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
2 years ago
In a group of 140 adults, 92 watch tennis, 81 play a sport and 40 do neither. Find the probability that an adult chosen at rando
likoan [24]

Answer:

PROBABILITY =11/140 or 8% (approx.)

8 0
2 years ago
Read 2 more answers
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