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2 years ago

How does Brandon's sound intensity level compare to ahmad's?

Mathematics

1 answer:

sergejj [24]2 years ago

7 0

we know that

$L=10log(\frac{I}{I0} )$

Find the value of L for Brandon

$L=10log(\frac{10^{-10}}{10^{-12}} )$

$L=10*2=20$

Find the value of L for Ahmad

$L=10log(\frac{10^{-4}}{10^{-12}} )$

$L=10*8=80$

therefore

the answer is

Brandon's sound intensity level is (1/4) the level of Ahmad

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Step-by-step explanation:

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2 years ago

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2 years ago

Your tea her will grade your response 4-8 to ensure you receive proper credit

svlad2 [7]

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3 years ago

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KATRIN_1 [288]

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point T is located at 9.

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According to the given details,

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Through this we know that,

=> SR + RT = 12 ---------------------(1)

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To know more about Number line Here

brainly.com/question/13425491

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1 year ago

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