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neonofarm [45]
3 years ago
8

How does Brandon's sound intensity level compare to ahmad's?

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

we know that

L=10log(\frac{I}{I0} )

Find the value of L for Brandon

L=10log(\frac{10^{-10}}{10^{-12}} )

L=10*2=20

<u>Find the value of L for Ahmad</u>

L=10log(\frac{10^{-4}}{10^{-12}} )

L=10*8=80

therefore

<u>the answer is</u>

Brandon's sound intensity level is (1/4) the level of Ahmad

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