A standard deck of 52 cards has 4 suits (spades, clubs, hearts, and diamonds) with 13 different cards (ace, 2, 3, 4, 5, 6, 7, 8,
Inessa [10]
Answer:
P(a pair with matching cards in different suits) = 1/52
Step-by-step explanation:
We are told that there are 4 suites and each suit has 13 different cards. This is a total of 52 cards.
Thus;
Probability of selecting one card of a particular suit = 13/52 = 1/4
If we now want to select a matching card of another suit without replacing the first one, then, we now have; 52 - 13 = 39 cards. Now, there are only 3 matching cards of the 3 remaining suits that is same as the first card drawn.
Thus; probability = 3/39 = 1/13
Thus;
P(a pair with matching cards in different suits) = 1/4 × 1/13
P(a pair with matching cards in different suits) = 1/52
Answer:
B. The sum function is linear but the volume function is not
Step-by-step explanation:
We are given that<u> f(x) and g(x) are linear</u>. Due to this, the sum function S(x) is linear.
And we know the shape of our figure, so we just need to <u>multiply the dimensions</u> for V(x) but <u>the product of three linear functions results in a cubic function, </u>and we conclude V(x) is not linear.
Glad to answer.
Answer:
s=80
Step-by-step explanation:
5/8ths is .625
80 x .625 =50
Well the probabilities of one or more different outcomes have to add up to 100%. You can't have one outcome be 90% and another be 20% because it does not equal 100%.
So if you know the percentage of one outcome you have to subtract that from 100%
That means C is your answer.
Part A
4 < 5 < 9 is given to us. Apply the square root to each term to end up with this inequality: sqrt(4) < sqrt(5) < sqrt(9)
So sqrt(5) is between <u>sqrt(4)</u> and <u>sqrt(9)</u>
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Part B
Simplify those two mentioned square roots
sqrt(4) = sqrt(2^2) = 2
sqrt(9) = sqrt(3^2) = 3
Therefore, sqrt(5) is also between <u>2</u> and <u>3</u>
We can see this through using a calculator: sqrt(5) = 2.23607 approximately
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Part C
We can now say:
2 < sqrt(5) < 3
Multiply all three sides by 6
6*2 < 6*sqrt(5) < 6*3
So the expression 6*sqrt(5) is between <u>6 x 2</u> and <u>6 x 3</u>
Sure enough, a calculator confirms this
6*sqrt(5) = 13.416408
since 6*2 = 12 and 6*3 = 18. We see that 13.416 is between 12 and 18.