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3 years ago

Which equation is true if S = -3

Mathematics

2 answers:

Effectus [21]3 years ago

8 0

<h3>i would like to help BUT where is the question ????</h3><h2>ԅ(¯﹃¯ԅ)ԅ(¯﹃¯ԅ)</h2>

adell [148]3 years ago

4 0

Can you put up a picture I’m confused

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What fraction has a decimal value between 1/2 and 3/4

andreyandreev [35.5K]

To find the decimal value, we must convert 1/2 and 3/4 into decimal.
1/2=0.5
3/4=0.75
Now we just have choose a random decimal in between the decimal.
Let's choose 0.6
Now we have to convert the decimal into a fraction. So we'll multiply the decimal by100.
0.6×100=60
Then we make the 60 into a fractions. 60/100
Then we'll simply the fraction. 60/100÷10=6/10÷2=3/5
There you go. You have your answer.

7 0

3 years ago

Read 2 more answers

What curve passes through the point (1 ,2) and has an arc length on the interval [2,6] given by Integral from 2 to 6 StartRo

Georgia [21]

Answer:

Step-by-step explanation:

Given

Length of curve

$L=\int_{2}^{6}\sqrt{1+64x^{-6}}dx$

Length of curve is given by

$L=\int_{a}^{b}\sqrt{1+\left ( \frac{\mathrm{d} y}{\mathrm{d} x}\right )^2}dx$ over interval a to b

comparing two we get

$\frac{\mathrm{d} y}{\mathrm{d} x}=8x^{-3}$

$dy=8x^{-3}dx$

integrating

$\int dy=\int 8x^{-3}dx$

$y=-4x^{-2}+C$

Curve Passes through (1,2)

$1=-4+C$

$C=5$

curve is

$y+\frac{4}{x^2}=5$

3 0

3 years ago

Find the derivative of the inverse function of the original function f(x)=(x+1)^3-5

____ [38]

Answer:

Step-by-step explanation:

let f(x)=y

$y=(x+1)^{3} -5\\flip ~x~and~y\\x=(y+1)^{3}-5\\(y+1)^{3}=x+5\\y=(x+5)^{\frac{1}{3} } -1\\or~f^{-1}(x)=(x+5)^{\frac{1}{3} } -1\\(f^{-1})'(x)=\frac{1}{3} (x+5)^{\frac{-2}{3} }$

4 0

3 years ago

Is the square root of 33 irrational?

maks197457 [2]

I’m gonna say no since it’s 5.74 and it isn’t repeating

6 0

3 years ago

Which equation could represent a circle with a center located at (11,-5)

Anon25 [30]

The standard equation of a circle is:

$(x-h)^2-(y-k)^2=r^2$ where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.

$(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64$

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0

3 years ago