Express r=2cos(theta)+2sin(theta) as a cartesian function.

1 answer:

3 0

The function is in polar coordinates.

When this is the case, to pass to rectagular (cartesian) coordinates you use:

x = r cos(theta)
y = r sin(theta)

Then,

x = [2cos(theta) + 2sin(theta)]cos(theta) =

= 2 [cos(theta)]^2 + 2sin(theta)cos(theta) = 2 [cos(theta)]^2 + sin(2theta)

y = [2cos(theta) + 2sin(theta)]sin(theta) =

= 2 cos(theta)sin(theta) + 2[sin(theta)]^2 = sin(2theta) + 2[sin(theta)]^2

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3 years ago

Consider the expressions 3x(x − 2) + 2 and 2x2 + 3x − 18.

Rzqust [24]

Answer:

See answer below

Step-by-step explanation:

For the first expression

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we get the exact same values when doing the evaluation at these two points.

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2 years ago

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Nataly [62]

Answer: $454.55

Step-by-step explanation:

Tito's weekly salary is always $ 500 per week.

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If we call x the dollar amount of all sales made by Tito in a week, then his income z(x) is given by the following equation:

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