Answer:
The temperature will decrease to 50 K
Explanation:
Step 1: Data given
Temperature = 127 °C = 400 K
Pressure = 2.00 atm
The pressure decreases to 0.25 atm
Volume and number of moles do not change
Step 2: Calculate the new pressure
p1/T1=p2/T2
⇒with p1 = The initial pressure = 2.00 atm
⇒with T1 = The initial temperature = 127 °C = 400 K
⇒with p2 = the new pressure = 0.25 atm
⇒with T2 = the new temperature = TO BE DETERMINED
2.00 atm / 400 K = 0.25 atm / T2
0.005 = 0.25 / T2
T2 = 0.25/0.005
T2 = 50 K
The temperature will decrease to 50 K
<u>Answer:</u> The number of moles of nitrogen gas is 0.505 moles.
<u>Explanation:</u>
To calculate the number of moles of nitrogen gas, we use ideal gas equation, which is:
where,
P = pressure of the gas = 4.27 atm
V = Volume of the gas = 2.96 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of gas = ?
Putting values in above equation, we get:
Hence, the number of moles of nitrogen gas is 0.505 moles.
Answer: 41.46 L
Explanation:
La ecuación que describe relación entre presión, volumen, temperatura y la cantidad (en moles)
de un gas ideal es:
PV = nRT
Donde: P = Presión absoluta
, V= Volumen , n = Moles de gas
, R = Constante universal de los gases ideales, T = Temperatura absoluta,
R = 0.082 L. atm/mol. °K
V = nRT/P
Calculanting n
n = mass/ molecular mass
<h3>n = 4 g / 2g. mol⁻¹</h3><h3>n = 2 mol</h3><h3>T =25⁰ + 273 ⁰K = 298 ⁰K</h3><h3>V = (2 mol ₓ0.082 L. atm / mol.°K x 298 ⁰K) / 1.18 atm = 41.46 L</h3>
there is always the same number of atoms at start and end, no atoms 'disappear' and none are 'made'