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Fantom [35]
3 years ago
9

What anions generally form precipitates? What are the exceptions?

Chemistry
2 answers:
8_murik_8 [283]3 years ago
6 0

Answer:

Carbonates (CO3-2), phosphates (PO4-3) and sulfides (S-2) are insoluble.

The exceptions are the alkali metals and the ammonium ion.

sammy [17]3 years ago
5 0

OH−,S−2,CO3S−2, and PO−34 O H − , S − 2 , C O 3 S − 2 , a n d P O 4 − 3 will generally form precipitates with the exceptions being when the cations are: Li+,Na+,K+.

If you find this helpful, Mark me as brainlyiest!

If this is not the correct answer.. Please correct me!

~Angoraspinner (AKA jack)

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Explanation:

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A plane takes 230 passengers from New York to Chicago in 3 hours.
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2 years ago
4. Imagine you have a radioactive sample containing both Virtualium and decayed atoms of Virtualium. After analysis, you find it
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3 years ago
Why is the increasing amount of carbon dioxide being taken up by the oceans a cause for concern?
Anna007 [38]

Answer;

-More carbon dioxide causes an increase in carbonic acid (H2CO3) which leads to a decrease in the concentration of carbonate ion (CO32-).

Explanation;

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7 0
3 years ago
PLEASE HELP ME!!! ASAP
shtirl [24]

Answer:

Theoretical yield of the reaction = 34 g

Excess reactant is hydrogen

Limiting reactant is nitrogen

Explanation:

Given there is 100 g of nitrogen and 100 g of hydrogen

Number of moles of nitrogen = 100 ÷ 28 = 3·57

Number of moles of hydrogen = 100 ÷ 2 = 50

Reaction between nitrogen and hydrogen yields ammonia according to the following chemical equation

N2 + 3H2 → 2NH3

From the above chemical equation for every mole of nitrogen that reacts, 3 moles of hydrogen will be required and 2 moles of ammonia will be formed

Now we have 3·57 moles of nitrogen and therefore we require 3 × 3·57 moles of hydrogen

⇒ We require 10·71 moles of hydrogen

But we have 50 moles of hydrogen

∴ Limiting reactant is nitrogen and excess reactant is hydrogen

From the balanced chemical equation the yield will be 2 × 3·57 moles of ammonia

Molecular weight of ammonia = 17 g

∴ Theoretical yield of the reaction = 2 × 3·57 × 17 = 121·38 g

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