Answer:
6.)
7.) 134.4 g O₂
Explanation:
The unbalanced equation:
NH₃ (g) + O₂ (g) ---> N₂ (g) + H₂O (g) + energy
<u>Reactants</u>: 1 nitrogen, 3 hydrogen, 2 oxygen
<u>Products</u>: 2 nitrogen, 2 hydrogen, 1 oxygen
The balanced equation:
4 NH₃ (g) + 3 O₂ (g) ---> 2 N₂ (g) + 6 H₂O (g) + energy
<u>Reactants</u>: 4 nitrogen, 12 hydrogen, 6 oxygen
<u>Products</u>: 4 nitrogen, 12 hydrogen, 6 oxygen
To convert from moles to grams, you need to multiply the starting value (4.2 moles) by the molar mass (32.00 g/mol). The molar mass can serve as a conversion because it technically means there are 32.00 grams O₂ per every 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator).
4.2 moles O₂ 32.00 g
-------------------- x ---------------- = 134.4 g O₂
1 mole
Answer:
Explanation:
Hello!
In this case, for the separation of the benzene-toluene mixture, we can use the following mole balances including the given mole fraction at each stream per species:
That can be solved by using a solver for P1 (benzene-rich flow) and P2 (toluene-rich flow):
Best regards!
Answer:
Well, that was just me........................
Answer:
0.0375 moles HBr
Explanation:
we are given;
- Molarity of HBr solution as 0.15 M
- Volume of the solution as 250 mL
We are required to determine the number of moles;
We need to know that;
Molarity = Moles ÷ Volume
Therefore;
Moles of HBr = Molarity of HBr solution × Volume of solution
Thus;
Moles of HBr = 0.15 M × 0.25 L
= 0.0375 Moles
Thus, the number of moles of HBr solute is 0.0375 moles
