The total end-to-end delay to send the packet length is L/R1 + L/R2. When using store-and-forward packet switches, the end-to-end delay is calculated as d = N × L/R.
<h3>How can you determine a packet's end-to-end delay?</h3>
- When using store-and-forward packet switches, the end-to-end delay for sending a single packet of length L across N connections, each with a transmission rate R, is d = N × L/R. (Queuing, propagation delay, and processing time are all ignored).
- The amount of time it takes a packet to travel from source to destination across a network is known as one-way delay (OWD).
- It is a term that is commonly used in IP network monitoring. It differs from round-trip time (RTT) in that it only measures the journey from source to destination in one direction.
- Propagation delay is the amount of time it takes for one bit to travel from the sender to the receiver end of a link.
- Propagation delay is defined mathematically as the distance between sender and receiver. Propagation delay ∝ 1 / transmission speed.
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Answer:
The first one. Important notice sum should be equal to zero before calculating the total sum.
Answer:
True
Explanation:
Because i have done it before and it works on an accer
Answer:
Segment registers
Explanation:
The initial purpose behind the segment registers was to enable a program to access many distinct (big) memory sections designed to be autonomous and part of a constant virtual store.
They don't have a processor-defined objective, but instead Operating system runs them for purpose. The GS register is used in Windows 64-bit to point to constructions defined by the operating scheme. Operating system kernels usually use FS and GS to access thread-specific memory. In windows, thread-specific memory is managed using the GS register. To access cpu-specific memory, the linux kernel utilizes GS.
Answer:
B.
Explanation:
A. is not the correct answer because that is called a LAN cable (ethernet)
C. is not correct because it has nothing to do with text messages or printing
D. is called a Bus, and isn't the right answer either