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Tasya [4]
4 years ago
11

Which polynomial could be represented by this graph?

Mathematics
1 answer:
Mkey [24]4 years ago
6 0

Answer:

x(x+2)(x-1)(x-3)^2

Please let me know the choices to better help you.

Step-by-step explanation:

I see zeros at x=-2 , x=0 , x=1 , x=3.

Any time it makes like a little U or upside down U at a zero you are going to have a even power on your factor (for which the zero occurs).  If it goes through the zero increasing or decreasing (not making a kind of U shaped upside down or upside right), it is an odd power.

So at x=-2, (x+2) is going to have an odd power

So at x=0,  (x-0) or (x+0) or even just x is going to have a odd power

So at x=1,  (x-1) is going to have an odd power

So at x=3, (x-3) is going to have an even power

So the polynomial could be represented by

x(x+2)(x-1)(x-3)^2

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An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.
Yakvenalex [24]

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Step-by-step explanation:

  • Let one integer be x
  • And other integer be y

x = 4y + 5

xy = 51

<u>According to </u><u>question </u><u>:</u>

➞ (4y + 5)y = 51

➞ 4y² + 5y = 51

➞ 4y² + 5y - 51 = 0

➞ 4y² + 17y - 12y - 51 = 0

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Hence,

➞ <u>y = 3</u>

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∴ The required integers are <u>3 and 17</u>

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Step-by-step explanation:

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