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3 years ago

Complete the sentence with the appropriate word.

Mathematics

2 answers:

Finger [1]3 years ago

8 0

Slope = y2-y1/ x2-x1 Here x1 is 4 Y1 is -7 X2 is 4 Y2is 8 Slope = 8-(-7)/4-4 = 15/0 Undefined

sergey [27]3 years ago

8 0

The best and most correct answer among the choices provided by your question is the second choice or letter B. <span>The slope of line CD is undefined.

By two-point slope form:
m=(y2-y1)/(x2-x1)
m=(8+7)/(4-4)
m=15/0 (undefined)
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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What is the measure of WUT?

Arada [10]

Answer:

38°

Step-by-step explanation:

4x-6x = -6 - 10

-2x = -16

__ __

-2 -2

x = 8

(6x-10)

(6(8)-10)

48-10

38°

6 0

3 years ago

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dangina [55]

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3 years ago

Read 2 more answers

After transforming f(x) = 2x² + 4x + 3 into vertex form, the vertex is easily identifiable. Which ordered pair is the vertex?

vagabundo [1.1K]

Answer:

The correct answer to your question is A because your asking for the vertex of the equation.

Step-by-step explanation:

Vertex Algebraic Equations

6 0

4 years ago

Help me on number 12 13 14 and 15

aleksandr82 [10.1K]

12. 1.625 [terminating]; 13. 0.83 [bar notation over 3 (repeating)]; 14. 900 cm = 9 m; 15. 0.23 cm = 2.3 mm

Repeating decimals are parts of decimals that have repetitive digits; terminating decimals are decimals whose digits end.

Whether you are using Metric or Imperial, you have to determine whether you are going from a small unit to a big unit or vice versa. Then perform your operation. So, in exercise 14, the smaller unit is centimeters, so you would be going from big to small. Exercise 15 has you going from small to big.

There are centimeters in one meter, so multiply 9 by to get 900 centimeters.

There are 10 millimeters in one centimeter, so divide 2.3 by 10 simply by moving the decimal point ONCE to the left [Power of 10].

small to BIG → Division

BIG to small → Multiplication

I am joyous to assist you anytime.

5 0

3 years ago

Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago