Complete question :
According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for the sale of 39 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in 2017. Useα = 0.05for the level of significance, and state your conclusion
Answer:
H0 : μ = 3
H1 : μ ≠ 3
Test statistic = 1.897
Pvalue = 0.0653
fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Step-by-step explanation:
Given :
Sample size, n = 40
Sample mean, x = 3.6
Population mean, μ = 3
Standard deviation, s = 2
The hypothesis :
H0 : μ = 3
H1 : μ ≠ 3
The test statistic :
(xbar - μ) ÷ (s/√n)
(3.6 - 3) / (2/√40)
0.6 / 0.3162277
Test statistic = 1.897
Using T test, we can obtain the Pvalue from the Test statistic value obtained :
df = n - 1; 40 - 1 = 39
Pvalue(1.897, 39) = 0.0653
Decison region :
If Pvalue ≤ α ; Reject the null, if otherwise fail to reject the Null.
α = 0.05
Pvalue > α ; We fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Substitute "d" = 2, 3.5 and 5 in the given equation and solve to get the "W" values for the respective days. Then plot the graph using days "d" in the "x" axis and weight "w" in the "y" axis the graph will be most definitely "Linear".
Answer:
D
Step-by-step explanation:
A function is any line that does not repeat in x-value (doesn't repeat on the x-axis).
Answer:
The first option
Step-by-step explanation:
Answer:
i would rather do 3% compounded interest
Step-by-step explanation:
Because it is monthly and i think the other one is yearly
