Answer:
GQ=25 units
Step-by-step explanation:
we know that
Point Q is the midpoint of GH
so
GH=GQ+QH and GQ=QH
GH=2GQ -------> equation A
we have
GH=5x-5
GQ=2x+3
substitute in the equation A and solve for x
5x-5=2(2x+3)
5x-5=4x+6
5x-4x=6+5
x=11
Find the length of GQ
GQ=2x+3
substitute the value of x
GQ=2(11)+3
GQ=25 units
Answer:
none
Step-by-step explanation:
We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.
According to the 'Law of Sines- Ambiguous Case', we have,
If a < b×sinA, then no triangle is possible.
If a = b×sinA, only one triangle is possible
If a > b×sinA, two triangles are possible.
So, we have,
b×sinA = 10 × sin30 = 10 × 0.5 = 5.
Now, as
4 = a < bsinA = 5.
We get, according to the rule, no triangle is possible.
The answer is 128 pi in^3. You have to multiply 4x4, then multiply that by 8 to get 128.
Y= -2x²-3x+2, (form y = ax² +b .x + c
The parabola opens downward & hence it's Vertex is a MAXIMUM.
We know that the axis of symmetry is -b/2a ==>3/(-4) ==>
x= - 3/4 (axis of symmetry. At x=-3/4 , y = 25/8 = 3.125
Hence the axis of symmetry is x= - 3/4 & the vertex is at (-3/4, 25/8)