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Serhud [2]
3 years ago
6

Determine the value of each expression. 10 • 17

Mathematics
2 answers:
Nata [24]3 years ago
5 0

Answer:

170

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />10 * 17

(10 * 10) + (10 * 7) + (0 * 10) + (0 * 7)

100 + 70 + 0 + 0

<u>Step 2:  Add</u>

<u />100 + 70 + 0 + 0

170 + 0

170

Answer:  170

weeeeeb [17]3 years ago
4 0

Answer:

170

Step-by-step explanation:

Simple, you need to multiply.

One way to think of it is to add a zero to 17. Which would be 170.

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2/6, 2/4, 2/10 please help with my with this like hurry when you see this pleaseeeee​
Vikentia [17]

Answer:

Step-by-step explanation:

I’m not sure if u mean dividing but this is dividing..2/6=3 2/4=2 2/10=5

5 0
4 years ago
If m 1 = 40, find the measure of 7
TEA [102]
M 7=280. you just multiply 7 by 40 to get your answer. i am pretty sure.
5 0
3 years ago
Read 2 more answers
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
4 years ago
What is the domain of the sine and cosine functions?
eimsori [14]

Answer:

domain of the sine and cosine functions is all real numbers

Step-by-step explanation:

range of both the sine and cosine functions is [−1,1]

graph can go left and right to infinity

graph goes up and down between 1 and -1

graph looks like a wave or

like U letters next to each other

UUUU

sine and cosine of an angle have the same absolute value as the sine and cosine of its reference angle.

mathlibretextsorg

8 0
2 years ago
Use the Distance Formula to find the distance between (13, 1) and (9,- 4), rounded to the nearest hundredth.
valina [46]

Answer:

  about 6.40 units

Step-by-step explanation:

The distance formula is ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

For the given points, the distance between them is ...

  d = √((9 -13)^2 +(-4-1)^2) = √((-4)^2 +(-5)^2) = √(16 +25)

  d = √41 ≈ 6.40

The distance between the points is about 6.40 units.

4 0
3 years ago
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