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SVETLANKA909090 [29]
3 years ago
13

Which describes the number and type of roots of the equation 4x^3-6x^2+15x+2=0?

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer: Non of the option.

Step-by-step explanation:

The given equation is

4x^3 - 6x^2 + 15x + 2 = 0

Let's test 1, if it's one of the root. I.e

If x = 1

4 - 6 + 15 + 2 = 15

Positive 1 is not a root to the equation

If x = - 1

-4 - 6 - 15 + 2 = - 23

Negative 1 is not a root

If x = 2

4x8 - 6×4 + 15×4 + 2

32 - 24 + 30 + 2 = 40

Positive 2 is not a root

If x = - 2

4×(-8) - 6×4 - 15×2 + 2

-32 - 24 - 30 + 2 = -84

Negative 2 is not a root

If x = 3

4×27 - 6×9 + 15×3 + 2

108 - 54 + 45 + 2 = 101

Since non of them tend to zero, non of the option is a root of the equation

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The average rate of change of f(x) on the interval [a,b] is f(b)−f(a)b−a.

We have that a=1254, b=6103100, f(x)=20(54)x.

Thus, f(b)−f(a)b−a=20(54)(6103100)−(20(54)(1254))6103100−(1254)=−58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100.

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