Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.

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2 years ago

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If t varies 1/s and t=2 when s=60 find the relationship between t and s, b, find the value of t when s=90 c, find s when t=2,1/2

suter [353]

Answer:

$t = k \frac{1}{s} \\ 2 = k. \frac{1}{60} \\ k = 120 \\ k \: \: is \: constant \: of \: variation \\ relationship \: is \\ t = \frac{120}{s} . \\ when \: s \: = 90 \\ t = \frac{120}{90} \\ t = \frac{4}{3} \\ when \: t = 2 \frac{1}{2} \\ s = \frac{120}{2 \frac{1}{2} } \\ s = 48$