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2 years ago

Alcohol promotes the premature production of urine which may lead to dehydration. True or false?

Mathematics

2 answers:

Sonja [21]2 years ago

5 0

Answer:

alcohol makes you dehydrated BUT

Step-by-step explanation:

it does not make you pee more so false

Marrrta [24]2 years ago

3 0

Answer:

False.

Step-by-step explanation:

The word Premature means early or occurring before a usual time.

That wouldn’t lead to dehydration. It would make you go to the bathroom much more often.

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Look at the following graph of the given equation. Determine whether the equation is the function. Explain why or why not.

Drupady [299]

Answer:

Step-by-step explanation:

It is a function. Every x has only 1 y associated with it. You cannot find an exception to this rule.

Stated another more common way: if you take a ruler and lay it flat on the graph so that the ruler is parallel to the y axis, you will find the ruler will go through only one y for every x. That's called the vertical line test.

3 0

3 years ago

Please answer the following;

34kurt

The Surface area of the cube will be 433.5 square feet. Then the correct option is C.

<h3>What is a surface area of a cube?</h3>

Suppose that: The side length of the considered cube is L units. Then, we get:

Surface area of that cube = 6L² square units.

Bella is wrapping a cube shape box that measures 8.5 inches along each side.

The edge length of the cube is 8.5 meters.

Then the Surface area of the cube will be

Surface area = 6 x 8.5²

Surface area = 6 x 72.25

Surface area = 433.5 square feet

The Surface area of the cube will be 433.5 square feet.

Then the correct option is C.

More about the surface area of the cube link is given below.

brainly.com/question/13789496

#SPJ1

6 0

2 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

2 years ago

Read 2 more answers

Please solve number 11:(

MrRa [10]

Answer:

Market price $400

Cost price $300

Step-by-step explanation:

MP: market price

CP: cost price

1. (MP x 0.9) - CP = 60

CP = 0.9MP - 60

2. MP - CP = 100

CP = MP - 100

0.9MP - 60 = MP - 100

MP - 0.9MP = 100 - 60

0.1MP = 40

MP = 400

Cost price = MP - 100 = 400 - 100 = 300

3 0

1 year ago

How do we use unit rate on every day life? What does unit rate show

NeTakaya

We use unit rate in every day life, for example, when comparing prices at stores. One store may offer five bowls for $7.99 and the other one bowl for $2.45.

5 0

3 years ago