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2 years ago

What is the equation of the line that passes through the points (-6,6) and (-1,-9)

Mathematics

1 answer:

IgorLugansk [536]2 years ago

6 0

Answer:

The answer to the question provided is y = -3x - 12.

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

$y = mx + b$

❃Incase you also forgot, what the slope formula is ☟

$m = \frac{y_2 - y_1 }{x_2 - x_1}$

➊ First: We are going to be solving for the slope.

$m = \frac{ - 9 - 6}{ - 1 - ( - 6)} = \frac{ - 15}{ \: \: \: 5} = - 3$

➋Second: We find the y-intercept.

$y = mx + b \\ 6 = - 3( - 6) + b \\ 6 = 18 + b \\ \frac{ - 18 = - 18 \: \: \: \: \: \: \: \: \: \: \: \: }{ - 12 = b}$

➌Third: Plug in.

$y = - 3x - 12$

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Why do you switch the inequality sign when multiplying or dividing by a negative?

Andreas93 [3]

If we multiply or divide both sides of an inequality by a negative number, you have to flip the inequality. Hope this helps :)

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2 years ago

Triangle abc is located on a coordinate plane angle c is at (1,2) the triangle is rotated counter clockwise 90° about the origin

sertanlavr [38]

After rotating a point C 90° counterclockwise about the origin the coordinates of C' would be (-2, 1)

In this question, we have been given a triangle ABC.

A point C is at (1, 2)

The triangle is rotated counter clockwise 90° about the origin.

We need to find the coordinates of C' which is image of vertex C after rotation.

We know that, if we rotate a point 90° counterclockwise about the origin a point (x, y) becomes (-y, x).

Here C(1, 2) is rotated 90 degrees counterclockwise about the origin.

So, the coordinates of C' would be,

C' = (-2, 1)

Therefore, after rotating a point C 90° counterclockwise about the origin the coordinates of C' are (-2, 1)

Learn more about the rotation here:

brainly.com/question/2763408

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6 months ago

A jacket is on sale for $15 off. As part of a one-day sale, a 20% discount is applied to all purchases. If x represents the orig

ahrayia [7]

(x-15).8 this is the answer

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2 years ago

Read 2 more answers

This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)

beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

$\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}$

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

$\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}$

But equation of a hyperbola is given as

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

Substituting the values of a, b, h and k, we have

$\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}$

Hence the answer is

$\frac{x^2}{1}-\frac{y^2}{3}=1$

5 0

4 months ago

I’m actually confused.

-BARSIC- [3]

M^2 + n^2

Step 1:
Substitute in the numbers
-5^2 + 3^2

Step 2:
Square both numbers
25 + 9

Step 3:
Add them together

Answer is 34

8 0

2 years ago