Answer:
b) 0.0007
c) 0.4163
d) 0.2375
Step-by-step explanation:
We are given the following:
We treat securities lose value as a success.
P(Security lose value) = 70% = 0.7
Then the securities lose value follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 20.
a) Assumptions
- There are 20 independent trials.
- Each trial have two possible outcome: security loose value or security does not lose value.
- The probability for success of each trial is same, p = 0.7
b) P(all 20 securities lose value)
We have to evaluate:
0.0007 is the probability that all 20 securities lose value.
c) P(at least 15 of them lose value.)
d) P(less than 5 of them gain value.)
P(gain value) = 1 - 0.7 = 0.3
Answer: 3 11/20
Step-by-step explanation:
You would first simplify 3 3/4 which is 15/4 then you would subtract it with 1/5
Next, you would have to find the GCD ( greatest common factor) for 15/4 and 1/5 which is 20 so multiply 15 by 5 and 4 by 5 which is 75/20, then multiply the top and bottom with 4 for 1/5 which is 4/20 . You then would subtract the simplified forms 75/20 with 4/20 Which is 71/20 which u can simplify to
3 11/20.
If you have a graphing calculator set it to radian mode and put these in there.
Answer:
The answer is,

Step-by-step explanation:

Firstly, you have to get rid of fraction by multiplying (r-3) to both side and expand out:
t × (r-3) = r/(r-3) × (r-3)
rt - 3t = r
Then you have to move all the "r" variables to one side and other variables to the other side:
rt - r = 3t
You can make "r" as a subject by taking out the common term, you can see that the common term on the left is "r" so you can bring out:
r(t-1) = 3t
r = 3t/(t-1)