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3 years ago

Maois, tricyclics, and ssris all produce which effect on neurons

1 answer:

8 0

Those are antidepressant drugs that increase the level of neurotransmitters.

Selective serotonin reuptake inhibitors (SSRIs) affect the process of neurotransmitters’ reabsorption back into nerve cells. This inhibitor prevents reuptake of serotonin and instead of that, the serotonin stays in the gap between the nerves-synapse.

Tricyclics are antidepressants that block the reabsorption of neurotransmitters, in this case, serotonin, and epinephrine. As a result, these chemicals are released into a synapse.

<span>Monoamine oxidase inhibitors (MAOIs) block the enzyme monoamine oxidase which breaks down serotonin, epinephrine, and dopamine. As a result, the levels of those neurotransmitters are increased.</span>

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If two genes are found on different chromosomes, or if they are far enough apart on the same chromosome that the chance of a cro

nika2105 [10]

Complete question:

A wild-type tomato plant (Plant 1) is homozygous dominant for three traits: solid leaves (MM), normal height (DD), and smooth skin (PP).

Another tomato plant (Plant 2) is homozygous recessive for the same three traits: mottled leaves (mm), dwarf height(dd), and peach skin (pp).

In a cross between these two plants (MMDDPP x mmddpp), all offspring in the F1 generation are wild type and heterozygous for all three traits(MmDdPp).

Now suppose you perform a testcross on one of the F1plants (MmDdPp x mmddpp). The F2 generation can include plants with these eight possible phenotypes:

solid, normal, smooth

solid, normal, peach

solid, dwarf, smooth

solid, dwarf, peach

mottled, normal, smooth

mottled, normal, peach

mottled, dwarf, smooth

mottled, dwarf, peach

Assuming that the three genes undergo independent assortment, predict the phenotypic ratio of the offspring in the F2 generation.

Answer and Explanation:

<u>Cross 1:</u>

Parental) MMDDPP x mmddpp

F1) MmDdPp

<u>Cross 2</u>: <em>Testcross</em>

Parental) MmDdPp x mmddpp

Gametes) MDP MdP MDp Mdp mDP mdP mDp mdp

mdp mdp mdp mdp mdp mdp mdp mdp

Punnet Square)

mdp

MDP MmDdPp

MdP MmddPp

MDp MmDdpp

Mdp Mmddpp

mDP mmDdPp

mdP mmddPp

mDp mmDdpp

mdp mmddpp

F2) 8/64 = 1/8 MmDdPp, solid leaves, normal height, smooth skin

8/64 = 1/8 MmddPp, solid leaves, dwarf height, smooth skin

8/64 = 1/8 MmDdpp, solid leaves, normal height, peach skin

8/64 = 1/8 Mmddpp, solid leaves, dwarf height, peach skin

8/64 = 1/8 mmDdPp, mottled leaves, normal height, smooth skin

8/64 = 1/8 mmddPp, mottled leaves, dwarf height, smooth skin

8/64 = 1/8 mmDdpp, mottled leaves, normal height, peach skin

8/64 = 1/8 mmddpp, mottled leaves, dwarf height, peach skin

Another way of predicting the phenotypic ratio of the offspring in the F2 generation is by performing a testcross for each gene by separately and then multiplying their genotypic proportions. This is:

<u><em>Leaves Gene</em></u>

Parental) Mm x mm

Gamtes) M m m m

Punnet Square) M m

m Mm mm

F2) 1/2 Mm

1/2 mm

Parental) Dd x dd

Gamtes) D d d d

Punnet Square) D d

d Dd dd

F2) 1/2 Dd

1/2 dd

Parental) Pp x pp

Gamtes) P p p p

Punnet Square) P p

p Pp pp

F2) 1/2 Pp

1/2 pp

To get the phenotypic ratio of the offspring we multiply the genotypic proportion for each trait by the genotypic proportions of the other two traits, like this:

For plants with solid leaves, normal height, smooth skin

solid leaves ratio -> 1/2

normal height ratio -> 1/2

smooth skin ratio -> 1/2

MmDdPp ratio: 1/2 x 1/2 x 1/2 = 1/8

For plants with solid leaves, dwarf height, smooth skin

MmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

For plants with solid leaves, normal height, peach skin

MmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

For plants with solid leaves, dwarf height, peach skin

Mmddpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

For plants with mottled leaves, normal height, smooth skin

mmDdPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

For plants with mottled leaves, dwarf height, smooth skin

mmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

For plants with mottled leaves, normal height, peach skin

mmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

For plants with mottled leaves, dwarf height, peach skin

mmddpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

3 0

3 years ago

Identity

-Dominant- [34]

The dermis is the layer of the skin where the sweat glands which work to cool your body are found.

<h3>What are sweat glands?</h3>

Sweat glands are glands which produce sweat which is helps to cool the body when the body is hot.

The sweat glands are found in the middle layer of the skin known as dermis.

The other layers of skin are the epidermis found in the outermost layer and the hypodermis found in the deepest layer of the skin.

Therefore, the dermis is the layer of th skin where the sweat glands which work to cool your body are found.

Learn more about dermis at: brainly.com/question/14501560

4 0

2 years ago

Why is carbon important for forming complicated molecules?

navik [9.2K]

<span>it can form four covalent bonds it forms very strong bonds

</span>

5 0

3 years ago

Which is an example of reverse polarity?

shutvik [7]

Answer:

The Answer Is C

Explanation:

<u>Please Like And Have A Good Day!!!!!!!!!!!!!!!</u>

5 0

3 years ago

In pea plants, the gene for the color of the seed has two alleles. In the following Punnett square shown below, the dominant all

Bogdan [553]

<h2>Question 1.</h2><h2>Answer:</h2>

The correct answer is option D which is 100%.

<h3>Explanation:</h3>

According to the description of Punnett square given in the question, there will be there will be two types of genotype and one type of phenotype which is yellow.

YY, homozygous dominant = Yellow Seeds.
Yy, heterozygous = Yellow Seeds
So the progeny will be 100% of yellow seeds.

Punnett square is also attached.

<h2>Question No.2.</h2><h2>Answer:</h2>

The correct answer is the option A which predicts the genotypic and phenotypic probabilities of possible.

<h3>Explanation:</h3>

<u><em>Punnett square is a way to determine the probable genotype of expected offspring by the genotypes of father and mother devised by Punnett.</em></u>

In this method, A square shaped table is constructed and the alleles of the gene of father/male are written on the top of tables, on the column.
The alleles of the mother are written in horizontal to square, in front of rows.
So the genotypes in the square box by multiplying row and column alleles will be expected genotype of an offspring.
The example is attached below.

<h2>Question no. 3.</h2><h2>Answer:</h2>

The correct answer is option C which is 1 = TT; 2 = Tt; 3 = Tt; 4 = tt .

<h3>Explanation:</h3>

The Punnett square is made by the description given in the question.

There are total 4 boxes. In box number 1 which is on top left genotype is TT and in box 2 which is on top right genotype is Tt. In box 3, the genotype is Tt and in box 4, the genotype is tt.

So according to the given Punnett square information in option C is correct one.

8 0

4 years ago