How many oxygen atoms are there in the product: 6Ca+4PO4→2Ca3(PO4)2? A. 16 B. 2 C. 4 D. 8

2 answers:

6 0

D, Since the oxygen molecule is in parenthesis on the product side of the equation (the right side of the arrow) you have to multiply the inside number by the outside number, so 4 × 2 = 8.

malfutka [58]3 years ago

6 0

Answer:

The correct answer is option A.

Explanation:

$6Ca+4PO_4\rightarrow 2Ca_3(PO_4)_2$

Number of molecules of $Ca_3(PO_4)_2$ =2

In 1 molecule $Ca_3(PO_4)_2$ , there are 8 oxygen atoms:

$4\times 2 = 8$ oxygen atoms.

Then 2 molecules of $Ca_3(PO_4)_2$ :

$2\times 8 = 16$ oxygen atoms.

Hence, the correct answer is option A.

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A 125 ml sample of gas is at STP how many moles of gas are in the sample

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5.58*10⁻³ moles of gas are in the sample.

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The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

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$amount of moles=\frac{0.125 L*1 mole}{22.4 L}$