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3 years ago

The table shows the number of reactants and products present during two separate chemical reactions.

Chemistry

1 answer:

aleksandr82 [10.1K]3 years ago

6 0

Answer: Option (a) is the correct answer.

Explanation:

A decomposition reaction is defined as a reaction where a compound dissociates into two or more atoms.

For example, $A \rightarrow B + C + D$

Whereas a chemical reaction in which two reactants combine together to result in the formation of a compound is known as a synthesis reaction.

For example, $A + B \rightarrow C$ is a synthesis reaction.

Thus, we can conclude that the statement chemical reaction A, because the reactant is a compound identifies the decomposition reaction and describes a substance is involved.

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For a science project, Janet performs four experiments that are supposed to show a chemical reaction. She displays her results i

Lina20 [59]

A. experiment 1 i believe its the best answer

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3 years ago

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Feliz [49]

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of $H_{2}O_{2}$ is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

$Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g$

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

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3 years ago

Which characteristics do Jupiter and Saturn share? Check all that apply

Natasha2012 [34]

Answer:

The correct answers are first, fourth, fifth

Explanation:

6 0

3 years ago

Read 2 more answers

1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percen

Naddik [55]

Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol

Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g

% of acetic acid in vinegar=8.64 %

% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0

3 years ago

Given the following reaction:

mojhsa [17]

Answer:

Option D. 17.5

Explanation:

Equiibrium is: CO + 2H₂ ⇄ CH₃OH

1 mol of CO is in equibrium with 2 moles of hydrogen in order to make, methanol.

Initially we have 0.42 moles of CO and 0.42 moles of H₂

If 0.29 moles of CO remained, (0.42 - 0.29) = 0.13 moles have reacted.

So in the equilibrium we may have:

0.29 moles of CO, and (0.42 - 0.13 . 2) = 0.16 moles of H₂

Ratio is 1:2, if 0.13 moles of CO haved reacted, (0.13 . 2) moles have reacted of hydrogen

Finally 0.13 moles of methanol, are found after the equilibrium reach the end.

Let's make expression for KC: [Methanol] / [CO] . [Hydrogen]²

0.13 / (0.29 . 0.16²)

Kc = 17.5

4 0

3 years ago