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Marianna [84]
2 years ago
8

Find the missing dimension of the triangle. A triangle with base labeled b, height labeled 6 feet, and height labeled 14 square

feet.
Mathematics
1 answer:
jarptica [38.1K]2 years ago
6 0

Answer:

4.67 feet

Step-by-step explanation:

The computation of missing dimension of the triangle is given below:

As we know that

Area of the triangle = 1 ÷ 2 × base × height

14 = 1 ÷ 2 × base × 6

14 = 3 × base

So, the base is

= 14 ÷ 3

= 4.67 feet

Here we assume the area to be 14 square feet

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Total amount of money she has=$40

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40-12=28

She has $28 dollars left to spend on her binders.

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From a cruising depth of 75 m below sea level (BSL) the Nautilus descended to 105 m BSL and then rose to 80 m BSL. What is the t
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3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

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3 years ago
What is relationship between the unit fractions,1/2 and1/10? Describe both the number and size of the parts
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The two fractions are divisible by 2, can be broken down 
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3 years ago
CAN SOMEONE HELP ME FIND THE DISTANCE..​
kirill115 [55]

The angle of elevation from point C to point A is 32^{\circ}

<em><u>Solution:</u></em>

Given that we have to find the angle of elevation from point C to Point A

Given in figure that, angle A = 58^{\circ}

Given is a right angled triangle ABC where angle B = 90^{\circ}

We have to find angle C

The angle sum property of a triangle states that the angles of a triangle always add up to 180°

Therefore, in given triangle ABC

angle A + angle B + angle C = 180

58^{\circ} + 90^{\circ} + C = 180^{\circ}

148^{\circ} + C = 180^{\circ}\\\\C = 180^{\circ} - 148^{\circ}\\\\C = 32^{\circ}

Therefore angle C = 32^{\circ}

5 0
3 years ago
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