Answer:
5.43×10¯³² J
Explanation:
From the question given above, the following data were obtained:
Wavelength (λ) = 3.66×10⁴ hm
Energy (E) =?
Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:
1 hm = 100 m
Therefore,
3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm
3.66×10⁴ hm = 3.66×10⁶ m
Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:
Wavelength (λ) = 3.66×10⁶ m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 3.66×10⁶ × f
Divide both side by 3.66×10⁶
f = 3×10⁸ / 3.66×10⁶
f = 81.97 Hz
Finally, we shall determine the energy of the photon. This can be obtained as follow:
Frequency (f) = 81.97 Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 81.97
E = 5.43×10¯³² J
Therefore, the energy of the photon is 5.43×10¯³² J
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