<h3>
Answer:</h3>
1100 mmHg
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Gas Laws</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 1.5 atm
[Solve] mmHg
<u>Step 2: Identify Conversions</u>
1 atm = 760 mmHg
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1140 mmHg ≈ 1100 mmHg
<u>Answer:</u> The temperature of the solution in Kelvins is 422.356 K
<u>Explanation:</u>
Temperature is defined as the measure of coldness or hotness of a body. It also determines the average kinetic energy of the particles in a body.
This term is expressed in degree Celsius, degree Fahrenheit and Kelvins. All these units are interchangeable.
The S.I unit of temperature is Kelvins.
We are given:
Temperature of a solution = 
Conversion used to convert degree Celsius and Kelvins is:
![T(K)=[273.15+T(^oC)]](https://tex.z-dn.net/?f=T%28K%29%3D%5B273.15%2BT%28%5EoC%29%5D)

Hence, the temperature of the solution in Kelvins is 422.356 K
Answer:
<h3>tartaric acids</h3>
The molecular formula of the citric acid is C6H8O7. The structure of citric acid is as follows: The acid present in tamarind is tartaric acid.
<h3>Vinegar- </h3>
Oxalic
do you have anymore numbers to add to this problem??
You need to first write a chemical equation and balance it
C₄H₁₀ + O₂ → CO₂ + H₂O
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
1.0 moles X moles
1.0 mol C₄H₁₀ (

) = 4 moles of CO₂