Answer:
0.1978
Step-by-step explanation:
According to the rule of BODMAS (or FEDMAS), let us do the bracket first.
26·11 = 286
Now, do the multiplication from the left.
12·121·3 = 4356
286·7 = 2002
Now, do the division from the left.
![\frac{\frac{4356}{2002} }{11}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B4356%7D%7B2002%7D%20%7D%7B11%7D)
![=\frac{4356}{2002(11)}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4356%7D%7B2002%2811%29%7D)
![=\frac{396}{2002}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B396%7D%7B2002%7D)
= 0.1978
Relative extrema occur where the derivative is zero (at least for your polynomial function).
So taking the derivative we get
<span>20<span>x3</span>−3<span>x2</span>+6=0
</span><span>
This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.</span>
Answer:
Yes
Step-by-step explanation:
4 < 3(2) + 6
4< 6+6
4 < 12
To do this subtract 2 from each side of the equation to get y = -5, so the value of y in this is -5. Hope this helps!
8.5 is the same as 8.50, right? So just take the digit in the hundredth place of both decimals and subtract. You'd be doing 0-4 so you can go ahead and borrow a number to make 10-4, which equals 6. So without subtracting 8.5 and 4.64, you can determine that 6 will be in the hundredth place. Hope this helps!