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aev [14]
3 years ago
14

3) Plasma occurs in electrical sparks. These sparks contain

Chemistry
2 answers:
Rudiy273 years ago
7 0

Answer:

C)  ions and electrons.

Explanation:

They are correct took the test

blsea [12.9K]3 years ago
4 0

Answer:

Explanation:

Plasma is the 4rth state of matter

Plasma is essentially composed of mixtures of ions and electrons .the ions and electrons are mixed containing equal amounts of positive and negative charges .

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i am making a solution, and i want to increase the rate at which the solute dissolves. Describe two ways I can achieve this.
Paladinen [302]
Heat the solvent/solution with the solute over a Bunsen burner whilst mixing it with a glass storing rod or break up the solid into a powder to increase its surface area and then mix it with the solvent/solution.
4 0
4 years ago
I REALLY NEED HELP PLEASE!!!!!!!!
Fudgin [204]

Answer: 1. The ratio of the reactant aluminum to the product aluminum sulphate is 2:1

2. Option D. 1,3,2,2

Explanation: 1. From the balanced equation:

2Al + 3H2SO4 -> Al2(SO4)3 + 3H2

2moles of Al produced 1mole of Al2(SO4)3. Therefore, the ratio will be 2:1

2. C2H4 + 3O2 ---> 2CO2 + 2H2O from the equation, the coefficients are 1,3,2,2

4 0
3 years ago
If heat is supplied to the stillpot too rapidly, the ability to separate two liquids by fractional distillation may be drastical
almond37 [142]

Answer:

Yes, it's temperature dependent

Explanation:

A good fractional distillation depends largely upon maintaining a temperature gradient within the column. Perfectly, the temperature at the bottom of the column should be close or similar to the boiling temperature of the solution in the pot, and it should reduce continuously in the column until it reaches the boiling point of the more volatile component at the top of the column. If the distillation flask is heated too quickly, the whole column will heat up almost distributively and eliminate the desired temperature gradient. The result will be little fractionation and separation of the components.

3 0
3 years ago
Brandon is traveling in France. He weighs himself at a health club because he is concerned that he has eaten too many croissants
anastassius [24]

<u>Answer:</u>

<u>For a:</u> Yes, he has gained weight.

<u>For b:</u> The number of onions required is 1.

<u>Explanation:</u>

  • <u>For a:</u>

We are given:

Weight of Brandon checked earlier = 183 lb

Converting this into kilograms, we use the conversion factor:

1 kg = 2.205 lb

So, 183lb\times \frac{1kg}{2.205lb}=83kg

And, weight of Brandon measured at the health club = 85.0 kg

As, the weight at the health club is more than the previous measured weight. So, Brandon has gained weight.

  • <u>For b:</u>

We are given:

Amount of diced onions a recipe calls = 125 g

Mass of 1 onion = 4 oz

Converting the mass of 1 onion to ounces, we use the conversion factor:

1 oz = 28.35 g

So, 4oz\times \frac{28.35g}{1oz}=113.4g

To calculate the number of onions, we use the equation:

\text{Number of onions}=\frac{\text{Mass of onion a recipe calls}}{\text{Mass of 1 onion}}

\text{Number of onions}=\frac{125g}{113.4g}=1.1\approx 1

Hence, the number of onions required is 1.

6 0
3 years ago
Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas
hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of  CS_2 = 1.20 mole

Moles of  Cl_2 = 3.60 mole

Volume of solution = 1.00  L

Initial concentration of CS_2 = \frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M

Initial concentration of Cl_2 = \frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M

The given balanced equilibrium reaction is,

                 CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Initial conc.         1.20 M        3.60 M                  0                  0

At eqm. conc.     (1.20-x) M   (3.60-3x) M   (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

Now put all the given values in this expression, we get :

K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}

Given :Equilibrium concentration of CCl_4 , x = \frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M

K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}

K_c=0.36

Thus equilibrium constant at unknown temperature is 0.36

4 0
3 years ago
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