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bogdanovich [222]
4 years ago
6

A. 6.07 x 10-15 How many significant figures are there in this equation

Chemistry
1 answer:
Harman [31]4 years ago
8 0

Answer:

3

Explanation:

In scientific notation, the number of integers in the first part will always be the amount of significant figures.

For example,

1) 1.542505 x 10^17 =7 significant figures

1) 1.54 x 10^17 =3 significant figures

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What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)
amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

4 0
3 years ago
The maximum allowable concentration of pb2+ ions in drinking water is 0.05 ppm (i.e., 0.05 g of pb2+ in 1 million grams of water
trasher [3.6K]
PbSO₄ partially dissociates in water. the balanced equation is;
                    
                       PbSO₄(s) ⇄  Pb²⁺(aq) + SO₄²⁻(aq)
Initial                                     -                -
Change             -X               +X           +X
Equilibrium                           X              X

Ksp           =    [Pb²⁺(aq)] [SO₄²⁻(aq)]
1.6 x 10⁻⁸  =    X * X
1.6 x 10⁻⁸  =    X²
          X    =   1.3 x 10⁻⁴ M
      
Hence the Pb²⁺ concentration in underground water is 1.3 x 10⁻⁴ M. 
[Pb²⁺]  = 1.3 x 10⁻⁴ M.
           = 1.3 x 10⁻⁴ mol / L x 207 g / mol 
           = 26.91 ppm

8 0
3 years ago
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3 years ago
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Name three of the most sensitive parts of your body (Appropriate parts. Ex: finger, wrist, shoulder, etc.)
yKpoI14uk [10]
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3 years ago
Which of the following atoms could have an expanded octet when it is the central atom in a covalent compound?a) B
miv72 [106K]

Answer:

only chlorine can expand its octet.

Explanation:

An atom can expand its octet is it has empty d orbital

the electronic configuration of given elements will be:

B : 1s2 2s2 2p1 [Valence shell n =2 no d orbital]

O :1s2 2s2 2p4 [Valence shell n =2 no d orbital]

F : 1s2 2s2 2p5 [Valence shell n =2 no d orbital]

Cl :1s2 2s2 2p6 3s2 3p5 3d0 [Valence shell n =2 no d orbital]

Out of given elements only chlorine has empty d orbitals in its valence shell

Thus only chlorine can expand its octet.

3 0
3 years ago
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