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Leokris [45]
2 years ago
6

calculate the molarity of a solution that contains 2 moles of NaOH dissolve in 0.5 liter of the solution

Chemistry
1 answer:
Anon25 [30]2 years ago
8 0

4M

Use the equation to find Molarity of M = n/V

n being the moles and V being the volume, in this case, the liters. With that, you take 2 and divide that by .5 to get the molarity of 4M.

Hope this helps!

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Wewaii [24]

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4 0
2 years ago
What is the nuclear binding energy of an atom that has a mass defect of 5.0446
notsponge [240]

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

4 0
3 years ago
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Answer: B longer wave

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2 years ago
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Nitella [24]

Answer:

Explanation:

M=D times V

Answer-3,633.84g

Rounded Answer (correct sig figs)- 3600g

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3 years ago
The Law of Multiple Proportions states that ____.
harkovskaia [24]

Answer: when two elements combine, A and B, the ratio of the weight of B combining with A is always a whole number

Explanation:

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