The problem deals with a division and the rest of it, that is dividing the total amount of pencils into 9 classrooms and the rest, lets express it as fraction:
935/9 = 103 + 8/9
that is, if we multiply 103*9 we get 927 and are 8 pencils left over, therefore, 8 pencils are donated to the library and each classroom gets 103 pencils, in total 935 pencils are donated.
X = large boxes and y = small boxes
x + y = 70.....x = 70 - y
60x + 65y = 4300
60(70 - y) + 65y = 4300
4200 - 60y + 65y = 4300
5y = 4300 - 4200
5y = 100
y = 100/5
y = 20 <=== the small boxes weigh 20 lbs
x + y = 70
x + 20 = 70
x = 70 - 20
x = 50 <== and the large boxes weigh 50 lbs
Step-by-step explanation:
si 3=1
1+1+1 = 3+3+3
3=9
Vejeieve veiiebd e628382628
7/10 m= 0.7 m
4.1÷0.7=5.85
You would round down 5.85 to just 5, because he cannot cut less than a whole strip.
To find the exact amount of wire used in 5 strips:
5×0.7= 3.5
4.1-3.5= 0.6 m will be leftover.