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m_a_m_a [10]
4 years ago
15

What is the degree of EMD and what is the degree for DMB

Mathematics
1 answer:
elena55 [62]4 years ago
8 0
EMD = 90 - DMC
EMD = 90 - 20
EMD = 70

Now, DMB = 180 - FMD
DMB = 180 - 90
DMB = 90

Hope this helps!
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Ali used the expressed 8+25×2-45 to find how many CDs he has. how many CDs dose he have
MatroZZZ [7]

Ali has 13 CD's

Here's how I got my answer:

Step 1: Simplify 25 * 2 to 50. Which leaves us with 8 + 50 - 45

Step 2: Simplify 50 - 45 to 5. Which leaves us with 8 + 5.

Step 3: Simplify 8 + 5, to get your answer, 13.

7 0
3 years ago
Read 2 more answers
Ariel made cupcakes to sell. 2/3 of them were chocolate chip,25% of the reminder was strawberry and the rest were 90 vanilla cup
Anton [14]

Answer:

Let x be the total number of cupcakes.

Chocolate chips =

\frac{2}{3} x

Strawberry =

\frac{1}{4}  \times  \frac{1}{3}  \\  =  \frac{1}{12} x

Vanilla =

x -  \frac{2}{3} x -  \frac{1}{12}x \\  =  \frac{1}{3} x -  \frac{1}{12} x \\   =  \frac{1}{4} x

given

\frac{1}{4} x = 90

x = 90 \div  \frac{1}{4}  \\  = 90 \times 4 \\  = 360

a)Number of Chocolate chip Cupcakes =

\frac{2}{3}  \times 360 \\  = 240

b)Number of Strawberry cupcakes =

\frac{1}{12}  \times 360 \\  = 30

8 0
3 years ago
List the < from the largest to smallest for ABC
devlian [24]

Answer: B

Step-by-step explanation:

Since AB < AC < BC, it follows that \angle C < \angle B < \angle A

4 0
2 years ago
What is one point that lies in the solution set of the
Vlad [161]
Substitute the given point (3, -2) in each condition
(i) y < -3; y ≤ (2/3)x - 4
-2 < -3 → False
Therefore, it is not a solution.
[Since the values of x and y must satisfy both the conditions, if one of them does not satisfy the condition then it is not necessary to check the other one.]
(ii) y > -3; y ≥ 2/3x - 4
-2 > -3 → True
y ≥ 2/3x - 4
-2 ≥ -2 → True
Therefore, it is a solution.
(iii) y < -3; y ≥ 2/3x - 4
-2 < -3 → False
Therefore, it is not a solution.
(iv) y > -2; y ≤ 2/3x - 4
-2 > -2 → False
Therefore, it is not a solution.
Thereofore, the system of linear inequalities having the point (3, -2) in its solution set is y > -3; y ≥ 2/3x - 4. Hope it helps you.
8 0
3 years ago
In equilateral ΔABC, AD, BE, and CF are medians. If FO = 4, then AE = A) 4 B) 4 3 C) 8 D) 12
vampirchik [111]

Firstly, we need to draw triangle

we know that

O is a centroid

and centroid divides median into 2:1

so,

\frac{CO}{FO} =\frac{2}{1}

we have FO=4

so, we can plug it

\frac{CO}{4} =\frac{2}{1}

CO=8

now, we can find CF

CF=OC+FO

CF=8+4

CF=12

now, we can see triangle ACF is a right angled triangle

so, we can use pythagoras theorem

x^2=(\frac{x}{2} )^2+12^2

now, we can solve for x

\frac{3x^2}{4}=144

x^2=192

x=8\sqrt{3}

Since, it is equilateral triangle

so,

AC=x=8\sqrt{3}

we know that

E is a mid-point

so,

AE=\frac{AC}{2}

now, we can plug values

AE=\frac{8\sqrt{3}}{2}

AE=4\sqrt{3}................Answer


5 0
3 years ago
Read 2 more answers
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