What is the slope of the linear relationship shown in this table of values?

Mathematics

2 answers:

ololo11 [35]3 years ago

6 0

Second answer choice

KATRIN_1 [288]3 years ago

4 0

Answer:

Step-by-step explanation:

To find the slope m use any 2 ordered pairs from the table.

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 4, 11) and (x₂, y₂ ) = (2, - 1)

m = $\frac{-1-11}{2+4}$ = $\frac{-12}{6}$ = - 2 → B

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Given vectors u = (-3,2) and v = (4,-1), if vector w=2u -3v, what is ||w|| ?

Brums [2.3K]

$\bf \begin{cases}
u=\ \textless \ -3,2\ \textgreater \ \\
2u=2\ \textless \ -3,2\ \textgreater \ \\
\qquad \ \textless \ 2\cdot -3,2\cdot 2\ \textgreater \ \\
\qquad \boxed{\ \textless \ -6,4\ \textgreater \ }\\
----------\\
v=\ \textless \ 4,-1\ \textgreater \ \\
3v=3\ \textless \ 4,-1\ \textgreater \ \\
\qquad \ \textless \ 3\cdot 4,3\cdot -1\ \textgreater \ \\
\qquad \boxed{\ \textless \ 12,-3\ \textgreater \ }
\end{cases}\qquad
\begin{array}{llll}
w=2u-3v\\\\
w=\ \textless \ -6,4\ \textgreater \ -\ \textless \ 12,-3\ \textgreater \ \\\\
w=\ \textless \ -6-12,4-(-3)\ \textgreater \ \\\\
w=\ \textless \ -18,4+3\ \textgreater \ \\\\
\boxed{w=\ \textless \ -18,7\ \textgreater \ }
\end{array}
\\\\\\
||w||\implies \sqrt{a^2+b^2}\implies ||w||=\sqrt{(-18)^2+(7)^2}\implies ||w||=373$