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WINSTONCH [101]
4 years ago
14

Brittany is planning a party with her parents.After collecting the following information from two possible locations,Brittany is

meeting with her parents to help decide which location they should choose.
Over-the Top party palace charges $100 for use of their location,plus $15 per person.

Make Em Envious Emporium charges $300 for use of their location,plus $10 per person.


How will they determine which location they should choose?justify your answer.
Mathematics
2 answers:
abruzzese [7]4 years ago
7 0
They will determine where they should go by finding out how many people are going. 
Ksju [112]4 years ago
6 0
To determine what location they should choose they should find the total cost of what it would be for everyone all together

For Over-the Top party palace they can use the equation 15p+100=c, where c is the total cost and p is the number of people. 

For Make Em Envious Emporium they can use the equation 10p+300=c, where c is the total cost and p is the number of people. 

Using these equations they can find out which location is cheaper for the amount of people going.
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Answer:

5 sqrt(10) = c

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

9^2 + 13^2 = c^2

81 + 169 = c^2

250 = c^2

Take the square root of each side

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8 0
3 years ago
Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6
Oksi-84 [34.3K]

Answer:

-1/3

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

9x^2-15x

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

9x^2-15x=6

Subtract 6 from both sides:

9x^2-15x-6=0

Divide everything by 3:

3x^2-5x-2=0

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0

Find the x using the Zero Product Property:

3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

x=-1/3

Assume that the correct symbol is >. Thus,

x>-1/3

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

9x^2-15x

0 is indeed less than six, so our first correct solution is:

x>-1/3

For the second one, do the same thing. We have:

x=2

Assume that the correct symbol is <. Thus:

x

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

9x^2-15x

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

x>-1/3 \text{ and } x

Together, we can write them as:

-1/3

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

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Step-by-step explanation:

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