1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Levart [38]
3 years ago
7

Multiply the following and combine terms where possible. -a(a-b-3)

Mathematics
1 answer:
Scrat [10]3 years ago
6 0

Answer:

-a^2 +ab +3a

Step-by-step explanation:

-a(a-b-3)

Distribute

-a*a -a*(-b) -a *(-3)

-a^2 +ab +3a

You might be interested in
Tenaya earned 82 points on one math test and 94 points on the next test. Elena earned 94 points on the first test and then 82 po
jek_recluse [69]

Answer:

Total test score of Tenaya and Elena are same.

Step-by-step explanation:

Given:

Points earned by Tenaya on one math test = 82

Points earned by Tenaya on next math test = 94

Points earned by Elena on first math test = 94

Points earned by Elena on next math test = 82

We need to Compare the total test scores for Tenaya to the total scores for Elena.

Solution:

First we will find the Total test score of Tenaya and Elena.

Now we can say that;

Total test score of Tenaya is equal to sum Points earned by Tenaya on one math test and Points earned by Tenaya on next math test.

framing in equation form we get;

Total test score of Tenaya  = 94+82 = 176\ points

Total test score of Elena is equal to sum Points earned by Elena on one math test and Points earned by Elena on next math test.

framing in equation form we get;

Total test score of Elena  = 94+82 = 176\ points

Hence from we can say that Total test score of Tenaya and Elena are same.

7 0
3 years ago
What’s the median of the data on the dot plot? HELP ITS DUE IN ONE HOUR
patriot [66]

Answer:

It is 1.5

Step-by-step explanation:

{0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 3, 4, 4, 11}

 the middle two are 1 and 2.

the mean of 1 & 2 is 1.5 now you have the median!

8 0
2 years ago
In a certain year, the population of Smallburg was $4{,}000.$ In the following year, the population increased by $15\%.$ What wa
makkiz [27]

Answer:

4,600

Step-by-step explanation:

To solve this problem, we need to multiply add 15% of 4,000 back to 4,000.

First, change 15% into a decimal:

15% -> \frac{15}{100} -> 0.15

Next, multiply 4,000 by 0.15:

x= 4,000(0.15)

x=600

The last step is to add the 600 back to 4,000:

4,000 + 600 = 4,600

The population of Smallburg the following year was 4,600.

5 0
3 years ago
Solve the proportion: 5/x+7=3/x+3
Allushta [10]

Answer:

x=3

Step-by-step explanation:

cross multiply

5(x+3)=3(x+7)

5x+15=3x+21

5x+15-3x=3x+21-3x

2x+15=21

2x+15-15=21-15

2x=6

x=3

7 0
3 years ago
My mom packed my lunch three of the past five days, so the probability of my mom packing my lunch is 3/5. Is this Experimental o
Crank

Answer:

definitely theoretical.  Seems how mom packed the lunch 3/5 times a week, the pattern will follow

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • Given two angles that measure 50 degrees and 80 degrees and a side that measures 4 feet, how many triangles, if any, can be cons
    5·2 answers
  • Find all solutions to the equation. (1 point) sin x = square root of three divided by two.
    7·2 answers
  • 1/7÷5/2=?<br> plzzzz help
    15·1 answer
  • Identify the dependent and independent variables: bicep size and the amount of time spent weightlifting at the gym. Choose all t
    7·1 answer
  • Write equations as sentence 9+x=10​
    12·2 answers
  • Select measurements that are equivalent. Select all that
    10·1 answer
  • 5 If the spinner landed on red 100 times
    9·1 answer
  • Using the grocery ad below, what is the cost of 3 pounds of pork chops, 4 pounds of Italian sausage links, and 1 pound of ground
    15·1 answer
  • 3. A line contains the points P (1,1) and Q (7,10) what is the slop of the line
    10·1 answer
  • 2/4 x 3/4=<br> 16 ounces is _ 1 pound
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!