Let the only force acting on the ball is the gravity (free-failing) and the ball was initially stationary
vo = 0
s = vot + 1/2 gt^2
s = 1/2 x 10 x (2.2) ^2 = 24.2 m
Answer
You did not give the whole picture, soory
Step-by-step explanation:
The answer is -4 because 4+2 is equal to 6 and then 6-2 is equal to 4 and then times into the number of 2 the answer is 4x2 is equal to 8 and then minus into the negative 5 an the answer is -4.
Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
----------
14+2x=62 (x=Pass cost)
-14 -14
(2x=48)/2
x=24
6.50+5.75+1.15x=18
12.25+1.15x=18
-12.25 -12.25
1.15x=5.75 divide both sides by 1.15
x=5
