What is the value of (-3 + 31) + (-2+31)?

Mathematics

2 answers:

SpyIntel [72]2 years ago

6 0

Answer:

Step-by-step explanation:

31-3=28

31-2=29

28+29=57

Effectus [21]2 years ago

5 0

-3+31-2+31= 57

Best of wishes!!

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Given circle P with arc AE=53, arc BA=68 and arc CB=72 match the following angles with their corresponding measurements

11Alexandr11 [23.1K]

From the diagram;
1. Angle 2 = ADB+BDH
= arcAB/2 +90
= 34 +90
= 124°

2. Angle 4= 90°,
Reason ; the angle between a tangent and a radius is equal to 90. A tangent is a line that touches the circumference of a circle once even if prolonged.

3. Angle 5 = 90 -BDC (note the acr subtends twice the angle it subtends on the circumference to the center.
= 90-arc BC/2
= 90-36
= 54°

4. Angle 6 = BFD
= 180-ADB-FBD
= 180-AB/2-DE/2
But DE = 180 -121 = 59
Therefore, BFD = 180 -34-29.5
= 116.5°

5. Angle 1 = 180- BFD (angles on a straight line add up to 180°)
= 180- 116.5
= 63.5°

6. Angle 3 = 180 -(ADB+BFD)
= 180 -(34 +116.5)
= 180- 150.5
= 29.5°
similarly angle 3 = DE/2 = 59/2 = 29.5°

7. Angle 8= 90, because BD is diameter;
angles subtended by a diameter to the circumference is always a right angle (90°)

8.Angle 7 = BE
but BE= AB+AE
= 68+ 53
= 121°

3 0

3 years ago

PLEASE HELP!!! I NEED THE ANSWER SOON :)

densk [106]

$y=2x \newline y= x^{2} -3$

Substitue 2x for y in the second equation:

$2x= x^{2} -3$

Rearrange to $a x^{2} +bx+c=0$ form:

$x^{2} -2x-3=0$

Factor:

$(x-3)(x+1)=0$

Zeros are $x=3$ and $x=-1$

To find y-coordinates of pts of intersection, plug these x-values into first equation to get $y=-2$ and $y=6$

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3 years ago

Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 7x2 + y2 and the

Akimi4 [234]

Letting $x=t$ , we get $y=3x^2=3t^2$ and $z=7x^2+y^2=7t^2+(3t^2)^2=7t^2+9t^4$ , so we can parameterize the intersection by

$\mathbf r(t)=\langle t,3t^2,7t^2+9t^4\rangle$

where $-\infty$ .

Image attached.