Consider the functions f(x)=4x+15 and g(x)=x^2-x+6. At what positive integer value of x does the quadratic function, g(x), begin
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<h3><u>Explanation</u></h3>
- Method 1 (Formula)
The vertex of Parabola is the maximum/minimum point depending on the value of a.
- Find Vertex
<u>h-value</u>
<u>k-value</u>
The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.
- Method 2 (Derivative)
This is Calculus method. We simply differentiate the function then substitute y' = 0.
- Differentiate Function
Substitute f'(x) = 0
Substitute x = -5/2 in the original equation.
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