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pogonyaev
3 years ago
8

A Chemist has 100g of 25% acid solution. How much of these solution he needs to drain and replace with 70% acid solution to obta

in 100g of 60% acid solution?
Mathematics
2 answers:
Lapatulllka [165]3 years ago
4 0
To solve this kind of problem,  there are two concepts: the total amount of solution and the total amount of acid

in this case, suppose there are x grams of the 25% solution, y grams of the 70% of soltuion
x + y = 100                             => y= 100-x
0.25x + 0.7y =0.6 *100  =60
replace y with 100-x:   0.25x + 0.7(100-x)=60
                                     0.45x=10
                                            x= 22.22
100-22.22=77.78
so he needs to drain about 77.78 grams of the solution. 


AURORKA [14]3 years ago
4 0

77.78 grams

<h3>Further explanation</h3>

<u>Given:</u>

A chemist has 100g of 25% acid solution.

<u>Question:</u>

How much of these solution he needs to drain and replace with 70% acid solution to obtain 100g of 60% acid solution?

<u>The Process:</u>

We will solve the chemical problem of mixed concentration. A chemist wants to get an acid solution with new concentrations. He needs to drain the initial solution and replace it with another concentration of an acid solution.

  • Let x grams 25% acid solution mixed with y grams of 70% acid solution to obtain 100g of 60% acid solution.
  • Remember, a chemist first had 100 grams of acid solution. Then the part he needs to drain is (100 - x) grams.

Let's arrange the equations.

\boxed{ \ x + y = 100 \ grams \ } \rightarrow \boxed{ \ y = 100 - x \ } \ ....... (Equation-1)

\boxed{ \ \frac{(x \ grams)(25 \%) + (y \ grams)(70 \%)}{100 \ grams} = 60 \% \ } ....... (Equation-2)

We work on Equation-2 first.

\boxed{ \ 25x + 70y = 6000 \ } \rightarrow \boxed{ \ 5x + 14y = 1200 \ } \ ... (Equation-2)

Substitute Equation-1 to Equation-2.

\boxed{ \ 5x + 14(100 - x) = 1200 \ }

\boxed{ \ 5x + 1400 - 14x = 1200 \ }

\boxed{ \ 5x - 14x = 1200 - 1400 \ }

\boxed{ \ - 9x = -200 \ }

Therefore, \boxed{ \ x = 22.22 \ grams \ }

Thus, he needs to drain \boxed{\boxed{ \ 100 \ grams - 22.22 \ grams = 77.78 \ grams \ }}

<h3>Learn more</h3>
  1. How many liters of the  50%  solution and how many liters of the  90%  solution will be used? brainly.com/question/13034221
  2. Calculating the pH value of weak base brainly.com/question/9040743
  3. About electrolyte and nonelectrolyte solutions brainly.com/question/5404753  

Keywords: a chemist, has 100g, 25% acid solution, how much, he needs, to drain, and replace with, 70%, to obtain, 60%, mixed, initial, new

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