Answer:
2,990,000
Explanation:
If 1 hectare = 10,000 M^2 and there are 299 worms in 1 square meter then
(299)(10,000)= how many worms in 1 hectacre
(299)(10,000)= 2,990,000
Answer:
im pretty sure its A. since it shows the sperm goin into the egg forming a thing
Answer:
Nutrient pollution is the process where too many nutrients, mainly nitrogen and phosphorus, are added to bodies of water and can act like fertilizer, causing excessive growth of algae. Nutrients can run off of land in urban areas where lawn and garden fertilizers are used
Explanation:
Answer:
Carrier proteins are involved in facilitated diffusion and active transport of substances out of or into the cell (e.g. diffusion of sugars, amino acids and nucleosides, uptake of glucose, transportation of salts, glucose, amino acids, etc.).
Explanation:
<h2>
The correct answer is: Both parent must be PP.</h2>
Explanation:
- The given question states that for flower color of the violet plants there are three phenotypes possible, purple, light purple and white.
- The flower color coding gene is governed by two variants or alleles in which there is an absence of complete dominance of one allele over the other as, if complete Mendelian dominance was there, only two phenotypes for flower color would have existed, purple and white, without the existence of any intermediate color, light purple.
- This indicates the existence of a Non-Mendelian pattern of inheritance with respect to the gene encoding for the violet flower color.
- As the intermediate phenotype of flower color is light violet, it indicates that in these plants neither of the two alleles are capable of showing dominance and this is an example of Incomplete dominance.
- Let the two alleles of the flower color coding gene be: P and p.
- Then the possible genotypes are: PP, Pp, pp.
- The corresponding phenotypes are: Purple, Light purple and White.
- Crossing all possible parents,
1. P P
P PP PP
Phenotypes (Purple) (Purple)
P PP PP
Phenotypes (Purple) (Purple)
2. P P
P PP PP
Phenotypes (Purple) (Purple)
p Pp Pp
Phenotypes (Light Purple) (Light Purple)
3. P p
P PP Pp
Phenotypes (Purple) (Light Purple)
p Pp pp
Phenotypes (Light Purple) (White)
4. P P
p Pp Pp
Phenotypes (Light Purple) (Light Purple)
p Pp Pp
Phenotypes (Light Purple) (Light Purple)
5. P p
p Pp pp
Phenotypes (Light Purple) (White)
p Pp pp
Phenotypes (Light Purple) (White)
6. p p
p pp pp
Phenotypes (White) (White)
p pp pp
Phenotypes (White) (White)
- According to the results of the above crosses, we find that the plant breeder should use such parents which are homozygous for the P allele, that is, both the parents must have the PP genotype. Then only all the offspring produced by crossing these parents will develop purple colored violet only.