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kodGreya [7K]
3 years ago
6

ABC city residents vote on construction of a new playground. The number of votes in favor of playground was 3500

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

70% in favor of building a new playground  

<em>3500 (</em><em>in favor</em><em>) + 1500 (</em><em>against it</em><em>) = 5000 (</em><em>total number votes</em><em>)</em>

<em />

<em>3500 (</em><em>in favor</em><em>)                                              1500 (</em><em>against it</em><em>)</em>

<em> -------------------    = 0.7 / 70%                          -------------------     =0.3 / 30%</em>

<em>5000 (</em><em>total</em><em>)                                                      5000 (</em><em>total</em><em>)            </em>

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A rectangle has a length of 2x+7 and a width of 3x+8.
Phantasy [73]

Answer:

Below.

Step-by-step explanation:

Perimeter = 2(2x + 7 + 3x + 8)

= 2(5x + 15)

= 10x + 30.

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The cost, C dollars, of hiring a taxi is given by the formula C=2.00+3/20n, where n is the number of tenths of a mile driven. Wh
Snezhnost [94]

C(n)=2.00+3.20n

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C(4)=2+3.20(4)

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The cost of the taxi is $14.80.

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3 years ago
103. Please help me!10 points! Thanks.
Inessa05 [86]
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8 0
3 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
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The cost of 40 candy bars is
Anon25 [30]
C) $20
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