Start at 16 and count up by 2 until 26.
The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.
We're told that HJ has length 7<em>x</em> - 27.
The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.
This means we have
7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)
Solve for <em>x</em> :
7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)
7<em>x</em> - 27 = 4<em>x</em> - 6
7<em>x</em> - 4<em>x</em> = 27 - 6
3<em>x</em> = 21
<em>x</em> = 21/3
<em>x</em> = 7
D. 0.65 since that equals 65% and 0.35 or 35% would equal 100
Since the scale is 1:83, the real airplane is 83 times longer than the model airplane.
real length = 10.5 in * 83 = 871.5 in
Now we convert 871.5 in into ft.
1 ft = 12 in, so 1 in = 1/12 ft
We divide the number of inches by 12 to find the number of feet.
871.5 in = 871.5/12 ft = 72.625 ft
