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3 years ago

A ladder is 50 inches tall. How tall is it in feet and inches?

Mathematics

1 answer:

Kobotan [32]3 years ago

5 0

Answer:

4 feet and 2 inches

Step-by-step explanation:

1 foot = 12 inches

x feet = 50 inches

1/12 = x/50 --> 50/12 --> 4 feet and 2 inches

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Help help help on this

pantera1 [17]

ANSWER

C. 2.402

EXPLANATION

Given that:

$log_{3}(2) = 0.631$

$log_{3}(7) = 1.771$

We want to evaluate:

$log_{3}(14) = log_{3}(2 \times 7)$

Use the product rule of logarithms.

$log_{a}(mn) = log_{a}(m) + log_{a}(n)$

$log_{3}(14) = log_{3}(2) + log_{3}(7)$

$log_{3}(14) = 0.631 + 1.771$

$log_{3}(14) = 2.402$

The third choice is correct.

7 0

3 years ago

Easy question please answer :)))

Burka [1]

Answer:

Angle CED must also measure 60°.

Because angle m is shown to be congruent to angles ABC and CDE, this means that angle m has a measure of 60 degrees.

There can only be 180 degrees in a triangle, so the measure of angle ACB must be 180-60-60, which equals 60 degrees.

Using the Vertical Angles Theorem, the measure of angle ACB is the same as the measure of angle CED.

Therefore, angle CED measures 60°.

Step-by-step explanation:

m, because Triangle ABC is similar to triangle EDC

m over 2, because Triangle ABC is congruent to triangle DCE

m + 60 degrees, because Triangle ABC is similar to triangle DCE

120 degrees − m, because Triangle ABC is congruent to triangle DCE

7 0

3 years ago

Read 2 more answers

Nick went bike ride to the store 5 miles away.If it took nick 1/2 of an hour to get there and 2/5 to get back,what was his avera

pav-90 [236]

Answer:

11.1m/s

Step-by-step explanation:

Given parameters:

Distance of store = 5miles

Time to store = $\frac{1}{2}$ hr

Time from store = $\frac{2}{5}$ hr

Unknown:

Average speed = ?

Solution:

Average speed is the total distance divided by the total time taken.

Average speed = $\frac{total distance}{total time taken}$

Total distance = distance to store + distance from store = 5 + 5 = 10miles

Total time taken = $\frac{1}{2}$ hr + $\frac{2}{5}$ hr = $\frac{9}{10}$ hr

Average speed = $\frac{10}{\frac{9}{10} }$ = 10 x $\frac{10}{9}$ = 11.1m/s

5 0

3 years ago

Will mark as brainliest if correct

stellarik [79]

Answer:

-2/3

Step-by-step explanation:

The only way the answer could be one is if the exponent is 0

So 3x-2=0:

3x = -2

x = -2/3

Hope this helps!

8 0

4 years ago

Of all the employees,what is the approximate relative frequency of Managers who worked more than 40 hours ?

elena-14-01-66 [18.8K]

Answer:

The approximate relative frequency of Managers who worked more than 40 hours will be $9.3\%$ .

Step-by-step explanation:

The complete question is mentioned below in the attached diagram.

From the question diagram which is attached below, it is clear that

there are total $86$ employees, and

there are $8$ are who work more than $40$ hours per week.

Hence, the approximate relative frequency of managers who worked more than 40 hours will be:

$\frac{8}{86}=0.093$

Which is is equal to $9.3\%$ .

Therefore, the approximate relative frequency of Managers who worked more than 40 hours will be $9.3\%$ .

5 0

3 years ago