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Llana [10]
3 years ago
13

Determine if y=3x-2 Is a function

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0
It is x inputs all have different y outputs in the equation
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Solve the equation for y.<br> yk+yv=r<br> y=?
SIZIF [17.4K]

Answer:

y = r / (k+v)

Step-by-step explanation:

First, you use the distributive property and take out y: y(k+v)=r

Then you divide both sides by (k+v): y<u>(k+v)/(k+v)</u> = r/(k+v)

Finally you get y = r / (k+v)

7 0
3 years ago
Can someone help me pls ?
miss Akunina [59]

Answer:

so the equation would be 4x (because he buys 4 books) + 0y (because he didn't buy any CDs) = 32 (or it could be $32). The slope would be 4.

Step-by-step explanation:

7 0
3 years ago
Given that the points (-1,6). (3,6), (3, 1), and (-1, 1) are vertices of a rectangle, how much shorter is the width than the len
Ksju [112]
Since the given coordinates are already in order,
then and two consecutive distances between the coordinates will give length and breadth,

Using distance formula,
\sqrt{ {( - 1 - 3)}^{2}  +  {(6 - 6)}^{2} }  \\  =  \sqrt{ { (- 4)}^{2} }  \\  =  \sqrt{16 }  \\  = 4
(we'll not consider the negative value since distances can't be negative)

Applying this again on 2nd and 3rd coordinates,
\sqrt{ {(3 - 3)}^{2} +  {(6 - 1)}^{2}  }  \\  =  \sqrt{ {5}^{2} }  \\  = 5
(we'll not consider the negative value since distances can't be negative)

Since length's always gotta be greater than bredth
therefore,
the difference will be 5-4= 1 units


Hence width is 1 unit shorter than length.



Note: Unit used is "unit/s"
6 0
4 years ago
Consider the characteristics of the graph. Which statement DOES NOT describe the data set?
serg [7]
A, the interquartile range is 10, does not fit.

The interquartile range is found by subtracting the upper quartile and the lower quartile; in a box-and-whisker plot these are the outer edges of the box.  In this case, they are 40 and 20; 40-20 = 20, not 10.
4 0
3 years ago
Read 2 more answers
Suppose you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. If you randomly
mina [271]

Answer:

(a) The probability you pass the exam is 0.0000501.

(b) The expected number of correct guesses is 7.5.

(c) The standard deviation is 2.372.

Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r}  ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 30

           r = number of success = at least 60%

           p = probbaility of success which in our question is the probability

                 of a correct answer, i.e; p = \frac{1}{4} = 0.25

Let X = Number of questions that are correct

So, X ~ Binom(n = 30 , p = 0.25)

(a) The probability you pass the exam is given by = P(X \geq 18)

Because 60% of 30 = 18

P(X \geq 18) = P(X = 18) + P(X = 19) +...........+ P(X = 29) + P(X = 30)

= \binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}

= 0.0000501

(b) The expected number of correct guesses is given by;

  Mean of the binomial distribution, E(X) =  n \times p

                                                                =  30 \times 0.25 = 7.5

(c) The standard deviation of the binomial distribution is given by;

      S.D.(X)  =  \sqrt{n \times p \times (1-p)}

                    =  \sqrt{30 \times 0.25 \times (1-0.25)}

                    =  \sqrt{5.625}  =  2.372                

8 0
4 years ago
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